NCERT Solutions for Class 7 Maths Chapter 8 Comparing Quantities (EX 8.1) Exercise 8.1

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NCERT Solutions for Class 7 Maths Chapter 8 Comparing Quantities (EX 8.1) Exercise 8.1

“Comparing Quantities ” refers to the quantitative relationship between two quantities that represents their respective quantities. It is simply a tool for comparing data.

The concepts of ratio and proportion are taught to students in Class 7th 8.1 Maths on Comparing Quantities. Additionally, they will learn about the Unitary Method, Percentages, And Simple Interest concepts and how to use them in real-world situations. This chapter also discusses the Conversion Of Fractions, Decimals, and Percentages into one another. If students had access to the NCERT Solutions Class 7 Maths Chapter 8 Exercise 8.1, learning would be simpler. Many sites offer the NCERT Solutions Class 7 Maths Chapter 8 Exercise 8.1, and it gets tough for them to understand which site they should refer to.

Students should refer to the Extramarks website for the NCERT Solutions Class 7 Maths Chapter 8 Exercise 8.1 as it is an authenticated website that provides reliable solutions to the students who are registered with it. The NCERT Solutions for Class 7 Maths Chapter 8 Exercise 8.1, Comparing Quantities, expands on this concept by giving comparisons of precise names in Mathematics, which are Ratios, Proportions, and Percentages. The Chapter deals with real-world problems that will assist students in comprehending how to compare quantities. It also explains the concepts of profit, loss, and basic interest. In addition to teaching whole numbers, NCERT Solutions Class 7 Maths Chapter 8 Exercise 8.1 teaches how to convert fractions and decimals into ratios and percentages.Students will learn some crucial information, such as the necessity of using the same unit when comparing any two quantities. The four quantities in question are said to be in proportion if any two ratios are equivalent.

Access NCERT Solutions for Class 7 Mathematics Chapter 8- Comparing Quantities

The best option for CBSE students to practise the chapter titled Comparing Quantities in terms of exam preparation is choosing the NCERT Solutions Class 7 Maths Chapter 8 Exercise 8.1. There are numerous exercises in this chapter. On the Extramarks website, in PDF format, it offers the NCERT Solutions Class 7 Maths Chapter 8 Exercise 8.1. Students can study this answer straight from the website or mobile application, or they can download it as needed. Extramarks’ internal subject-matter experts, carefully and in accordance with all CBSE regulations, solved the problems and questions from the exercise.

Any student in Class 7 who is familiar with all the concepts in the Mathematics textbook and is well-versed in all the exercises in it can easily achieve the highest scores on the final examination. Students may readily comprehend the types of problems that may be given in the examination from this chapter. They can also learn the chapter weightage in terms of overall grade by using the NCERT Solutions Class 7 Maths Chapter 8 Exercise 8.1 so that they can adequately prepare for the final examination.

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Exercise 8.1

The NCERT Solutions Class 7 Maths Chapter 8 Exercise 8.1 are available on the Extramarks website so that students may fully understand the material. The best professionals in India who are authorities in their fields are available on Extramarks to instruct the students. The website contains extensive media-based learning modules. It adds graphics and animations to its modules to encourage students to study.To help students prepare for and do well in the examination, Extramarks offers the NCERT Solutions Class 7 Maths Chapter 8 Exercise 8.1. The NCERT Solutions Class 7 Maths Chapter 8 Exercise 8.1 are based on the most recent syllabus of the CBSE Board.

Students can efficiently prepare for the board examination by practising the key questions for each chapter of the Class 7 Mathematics course. Complete solutions will be given to them. Students can refer to the NCERT Solutions Class 7 Maths Chapter 8 Exercise 8.1 on the internet if they are having difficulty understanding the topics. Students may study all the concepts by accessing the NCERT Solutions Class 7 Maths Chapter 8 Exercise 8.1 on the Extramarks website. Moreover, Extramarks provides instructors, allowing students to ask them any questions they may have regarding the NCERT Solutions Class 7 Maths Chapter 8 Exercise 8.1. To help students discover their areas of weakness so they may work on them and do well on the examination, teachers offer worksheets for their students. Students who are reluctant to ask their school teachers questions concerning the NCERT Solutions Class 7 Maths Chapter 8 Exercise 8.1 are assisted by Extramarks tutors in clarifying their concepts.

NCERT Solutions for Class 7 Maths Chapter 8 Comparing Quantities Exercise 8.1

Students can adequately prepare for the chapter using the NCERT Solutions Class 7 Maths Chapter 8 Exercise 8.1. With the aid of the NCERT Solutions Class 7 Maths Chapter 8 Exercise 8.1, students may strengthen their fundamental understanding and get ready for any chapter-related issues. They can also practise past years’ papers and sample papers for improved preparation. Higher test scores are attained by those who understand the NCERT Solutions Class 7 Maths Chapter 8 Exercise 8.1  as a whole. The Extramarks website offers its students the opportunity to learn better with their experts’ published NCERT Solutions Class 7 Maths Chapter 8 Exercise 8.1.

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Q.1

Find the ratio of: a Rs 5 to 50 paise b 15 kg to 210 gc 9 m to 27 cm d 30 days to 36 hour

Ans.

( a ) Rs 5 to 50 paise 1 ruppe=100 paise So, 5 rupee=500 paise So, Rs 5 50 paise = 500 50 = 10 1 Thus, the required ratio is 10:1 . ( b ) 15 kg to 210 g 1 kg=1000 g So, 15 kg=15000 g So, 15 kg 210 g = 15000 210 = 500 7 Thus, the required ratio is 500:7 . ( c ) 9 m to 27 cm 1 m=100 cm So, 9 m=900 cm So, 9 m 27 cm = 900 27 = 100 3 Thus, the required ratio is 100:3 . ( d ) 30 days to 36 hour 1 day=24 hours So, 30 days=720 hours So, 30 days 36 hour = 720 36 = 20 1 Thus, the required ratio is 20:1 . MathType@MTEF@5@5@+= feaagKart1ev2aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbwvMCKf MBHbqeduuDJXwAKbYu51MyVXgaruWqVvNCPvMCG4uz3bqefqvATv2C G4uz3bIuV1wyUbqeeuuDJXwAKbsr4rNCHbGeaGqiVz0xg9vqqrpepC 0xbbL8F4rqqrFfpeea0xe9Lq=Jc9vqaqpepm0xbba9pwe9Q8fs0=yq aqpepae9pg0FirpepeKkFr0xfr=xfr=xb9adbaqaaeGaciGaaiaabe qaamaaeaqbaaGceaqabeaadaqadaqaaiaabggaaiaawIcacaGLPaaa caqGGaGaaeOuaiaabohacaqGGaGaaeynaiaabccacaqG0bGaae4Bai aabccacaqG1aGaaGimaiaabccacaqGWbGaaeyyaiaabMgacaqGZbGa aeyzaaqaaiaaxMaacaaIXaGaaeiiaiaabkhacaqG1bGaaeiCaiaabc hacaqGLbGaeyypa0JaaeymaiaabcdacaqGWaGaaeiiaiaabchacaqG HbGaaeyAaiaabohacaqGLbaabaGaae4uaiaab+gacaqGSaGaaeiiai aaysW7caqG1aGaaeiiaiaabkhacaqG1bGaaeiCaiaabwgacaqGLbGa eyypa0JaaeynaiaabcdacaqGWaGaaeiiaiaabchacaqGHbGaaeyAai aabohacaqGLbaabaGaae4uaiaab+gacaqGSaGaaeiiamaalaaabaGa aeOuaiaabohacaqGGaGaaGynaaqaaiaaiwdacaaIWaGaaeiiaiaabc hacaqGHbGaaeyAaiaabohacaqGLbaaaiabg2da9maalaaabaGaaGyn aiaaicdacaaIWaaabaGaaGynaiaaicdaaaGaeyypa0ZaaSaaaeaaca aIXaGaaGimaaqaaiaaigdaaaaabaGaaeivaiaabIgacaqG1bGaae4C aiaabYcacaqGGaGaaeiDaiaabIgacaqGLbGaaeiiaiaabkhacaqGLb GaaeyCaiaabwhacaqGPbGaaeOCaiaabwgacaqGKbGaaeiiaiaabkha caqGHbGaaeiDaiaabMgacaqGVbGaaeiiaiaabMgacaqGZbGaaeiiam aaL4babaGaaeymaiaabcdacaqG6aGaaeymaaaacaGGUaaabaWaaeWa aeaacaqGIbaacaGLOaGaayzkaaGaaeiiaiaabgdacaqG1aGaaeiiai aabUgacaqGNbGaaeiiaiaabshacaqGVbGaaeiiaiaabkdacaqGXaGa aGimaiaabccacaqGNbaabaGaaeymaiaabccacaqGRbGaae4zaiabg2 da9iaabgdacaqGWaGaaeimaiaabcdacaqGGaGaae4zaaqaaiaabofa caqGVbGaaeilaiaabccacaqGXaGaaeynaiaabccacaqGRbGaae4zai abg2da9iaabgdacaqG1aGaaeimaiaabcdacaqGWaGaaeiiaiaabEga aeaacaqGtbGaae4BaiaabYcacaqGGaWaaSaaaeaacaaIXaGaaGynai aabccacaqGRbGaae4zaaqaaiaaikdacaaIXaGaaGimaiaabccacaqG Nbaaaiabg2da9maalaaabaGaaGymaiaaiwdacaaIWaGaaGimaiaaic daaeaacaaIYaGaaGymaiaaicdaaaGaeyypa0ZaaSaaaeaacaaI1aGa aGimaiaaicdaaeaacaaI3aaaaaqaaiaabsfacaqGObGaaeyDaiaabo hacaqGSaGaaeiiaiaabshacaqGObGaaeyzaiaabccacaqGYbGaaeyz aiaabghacaqG1bGaaeyAaiaabkhacaqGLbGaaeizaiaabccacaqGYb GaaeyyaiaabshacaqGPbGaae4BaiaabccacaqGPbGaae4Caiaabcca daqjEaqaaiaabwdacaqGWaGaaeimaiaabQdacaqG3aaaaiaac6caae aadaqadaqaaiaabogaaiaawIcacaGLPaaacaqGGaGaaeyoaiaabcca caqGTbGaaeiiaiaabshacaqGVbGaaeiiaiaabkdacaqG3aGaaeiiai aabogacaqGTbaabaGaaeymaiaabccacaqGTbGaeyypa0Jaaeymaiaa bcdacaqGWaGaaeiiaiaabogacaqGTbaabaGaae4uaiaab+gacaqGSa GaaeiiaiaabMdacaqGGaGaaeyBaiabg2da9iaabMdacaqGWaGaaeim aiaabccacaqGJbGaaeyBaaqaaiaabofacaqGVbGaaeilaiaabccada WcaaqaaiaaiMdacaqGGaGaaeyBaaqaaiaaikdacaaI3aGaaeiiaiaa bogacaqGTbaaaiabg2da9maalaaabaGaaGyoaiaaicdacaaIWaaaba GaaGOmaiaaiEdaaaGaeyypa0ZaaSaaaeaacaaIXaGaaGimaiaaicda aeaacaaIZaaaaaqaaiaabsfacaqGObGaaeyDaiaabohacaqGSaGaae iiaiaabshacaqGObGaaeyzaiaabccacaqGYbGaaeyzaiaabghacaqG 1bGaaeyAaiaabkhacaqGLbGaaeizaiaabccacaqGYbGaaeyyaiaabs hacaqGPbGaae4BaiaabccacaqGPbGaae4CaiaabccadaqjEaqaaiaa bgdacaqGWaGaaeimaiaabQdacaqGZaaaaiaac6caaeaadaqadaqaai aabsgaaiaawIcacaGLPaaacaqGGaGaae4maiaaicdacaqGGaGaaeiz aiaabggacaqG5bGaae4CaiaabccacaqG0bGaae4BaiaabccacaqGZa GaaeOnaiaabccacaqGObGaae4BaiaabwhacaqGYbaabaGaaeymaiaa bccacaqGKbGaaeyyaiaabMhacqGH9aqpcaqGYaGaaeinaiaabccaca qGObGaae4BaiaabwhacaqGYbGaae4CaaqaaiaabofacaqGVbGaaeil aiaabccacaqGZaGaaeimaiaabccacaqGKbGaaeyyaiaabMhacaqGZb Gaeyypa0Jaae4naiaabkdacaqGWaGaaeiiaiaabIgacaqGVbGaaeyD aiaabkhacaqGZbaabaGaae4uaiaab+gacaqGSaGaaeiiamaalaaaba GaaG4maiaaicdacaqGGaGaaeizaiaabggacaqG5bGaae4Caaqaaiaa iodacaaI2aGaaeiiaiaabIgacaqGVbGaaeyDaiaabkhaaaGaeyypa0 ZaaSaaaeaacaaI3aGaaGOmaiaaicdaaeaacaaIZaGaaGOnaaaacqGH 9aqpdaWcaaqaaiaaikdacaaIWaaabaGaaGymaaaaaeaacaqGubGaae iAaiaabwhacaqGZbGaaeilaiaabccacaqG0bGaaeiAaiaabwgacaqG GaGaaeOCaiaabwgacaqGXbGaaeyDaiaabMgacaqGYbGaaeyzaiaabs gacaqGGaGaaeOCaiaabggacaqG0bGaaeyAaiaab+gacaqGGaGaaeyA aiaabohacaqGGaWaauIhaeaacaqGYaGaaeimaiaabQdacaqGXaaaai aac6caaaaa@A847@

Q.2

In a computer lab, there are 3 computers for every 6students.How many computers will be needed for 24students?

Ans.

For 6 students, number of computers required=3 So, for 1 student, number of computers required= 3 6 = 1 2 Thus, for 24 students, number of computers required= 1 2 ×24 = 12 Therefore, 12 computers are needed for 24 students.

Q.3

Population of Rajasthan=570 lakhs and population of UP=1660 lakh Area of Rajasthan= 3 lakh km2 and area of UP = 2 lakh km2.i How many people are there per km2 in both these States? ii Which State is less populated?

Ans.

(i) Population of Rajasthan in 3 lakh km 2 =570 lakhs Population of Rajasthan in 1 lakh km 2 = 570 3 = 190 Population of UP in 2 lakh km 2 =1660 lakhs Population of UP in 1 lakh km 2 = 1660 2 = 830 (ii) From above data, clearly Rajasthan is less populated.

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