NCERT Solutions for Class 7 Maths Chapter 3 Data Handling (EX 3.1) Exercise 3.1

Humans place a great deal of importance on Mathematics in their daily lives. There are numerous lucrative career opportunities, as well as research opportunities, associated with this academic field. There is no doubt that mathematics is one of the most organised and vital scientific disciplines. Indian mathematicians have a long history of impressing the world with their ingenuity and exceptional abilities. The subject of Mathematics is taught as a prominent scientific discipline from the earliest stages of school education itself, and students are encouraged to constantly strive to improve their understanding of it. The importance of Mathematics as an academic subject cannot be overstated. Mathematics has always piqued the curiosity of students. While some students struggle with it, others relish the challenges. Students may find it difficult to finish the exercises provided in their prescribed NCERT textbooks because they may find it difficult to comprehend the themes on their first attempt. Despite the fact that learning something new is never simple, once they have mastered it, they will feel tremendously satisfied.

With the help of the NCERT Solutions For Class 7 Maths Chapter 3 Exercise 3.1, students may complete Class 7 Maths Exercise 3.1. The exercises in the NCERT textbooks are always solved by students before they start a new chapter or theory. Students should practice NCERT solutions because doing so will help them understand the chapter’s concept and how it applies. Problem-solving and practice have a high priority in Mathematics. Statistics is a new subject for students in classes 10 and 11, as it is different from other chapters they have previously read. Students who are having trouble with Class 7 Maths Chapter 3 Exercise 3.1 can use the NCERT Solutions For Class 7 Maths Chapter 3 Exercise 3.1 to their advantage.

Students have a variety of possibilities if they want to pursue a more in-depth study of Mathematics. To make a sensible choice, it is, however, always advisable to be aware of one’s interests and skills. Before making a decision, students should research a variety of career options. Although each choice students make will provide them with a new opportunity, they will learn about themselves through fresh encounters and discoveries. No matter what they choose to pursue, students need to recognise that their efforts are always valuable. Students have a variety of possibilities if they want to pursue a more in-depth study of Mathematics. To make a sensible choice, it is, however, always advisable to be aware of one’s interests and skills. Students must ask for help if they feel they are answering a question too slowly. Instead of concentrating on the questions, they might ask their classmates and professors for help. In order to find the answers, they can also look in the NCERT Solutions For Class 7 Maths Chapter 3 Exercise 3.1, on the Extramarks mobile application and website. The NCERT Solutions For Class 7 Maths Chapter 3 Exercise 3.1 are provided to students in order to help them get past any challenges they may experience when learning data handling.

NCERT Solutions for Class 7 Maths Chapter 3 Data Handling (EX 3.1) Exercise 3.1 

The book published by the National Council for Educational Research and Teaching (NCERT) is the best source of information or textbook available to students for preparation for term-end or half-yearly exams of any class. Students can learn the fundamentals of each concept and subject matter via NCERT books. Teachers frequently prescribe the NCERT books as recommendations for test preparation. Many schools that are affiliated with the Central Board of Secondary Education (CBSE) include NCERT textbooks in their curricula. These schools use NCERT textbooks to instruct their students. NCERT is a government organisation created to offer educational resources for teachers and students to use in their studies and classroom instruction. The NCERT Solutions For Class 7 Maths Chapter 3 Exercise 3.1, provide answers to Exercise 3.1 of Chapter 3 of the NCERT textbook for Class 7.

Students should therefore concentrate on learning from and referring to the NCERT textbooks as they get ready for any exams or disciplines. The fact that NCERT provides educational resources and textbooks for all classes must be considered by students. For the answers to the exercises and questions provided in the NCERT textbooks of any subject and of any class, students can visit the Extramarks website. A good illustration of this is Chapter 3 of the NCERT Solutions For Class 7 Maths Chapter 3 Exercise 3.1. The NCERT Solutions For Class 7 Maths Chapter 3 Exercise 3.1 offer precise solutions to all of the Chapter 3 questions.

The NCERT Solutions For Class 7 Maths Chapter 3 Exercise 3.1, should be used as a practice resource by students. Due to the fact that the NCERT books present information about a single idea in a clear and concise manner, students should only learn from these. Students can grasp and determine how to apply concepts by using the questions in NCERT textbooks. However, if students need NCERT solutions, they can find them on the Extramarks website and Learning App. Students can view the NCERT Solutions For Class 7 Maths Chapter 3 Exercise 3.1, to see the methodology for solutions for Statistics.

Why Use Solved Class 11 Maths Exercises Solution NCERT

Students frequently skim over some subjects when studying for exams. This might be because, when students rapidly check their books before the test, some topics might be overlooked without understanding because they did not have enough time to completely read over each chapter. Students may experience difficulties if the subject turns out to be important. Students may encounter difficulties if a question from that subject is subsequently asked in an exam. Students should always review their notes and go over them to avoid this because the NCERT Solutions For Class 7 Maths Chapter 3 Exercise 3.1 include a synopsis of all the chapter’s subjects as well as questions from the exercise that may be asked in the tests. To avoid getting confused during the test, students should practice using the NCERT Solutions For Class 7 Maths Chapter 3 Exercise 3.1. Students should not take studying from NCERT textbooks lightly because it is an important part of their education. Various factors make solving NCERT textbooks important, and they can practice the exercises given in them using the NCERT Solutions For Class 7 Maths Chapter 3 Exercise 3.1. NCERT textbooks are essential to study because they provide the foundations for the more challenging questions on entrance examinations. This is something that students preparing for entrance exams like JEE or CUET should keep in mind. Students will not be able to respond to challenging questions if they have not completely read the chapter’s introductory information. The NCERT Solutions For Class 7 Maths Chapter 3 Exercise 3.1, must consequently be pursued by students.

The NCERT Solutions For Class 7 Maths Chapter 3 Exercise 3.1 provide an overview of the chapter. The NCERT Solutions For Class 7 Maths Chapter 3 Exercise 3.1 contain various important topics like the Introduction to Data Handling, Collecting Data, Organisation of Data, Representation of Values, Arithmetic Mean, Range, Mode, Mode of Large Data, Median, Use Of Bar Graphs with a Different Purpose, Choosing a Double Bar Graph, Drawing a Double Bar Graph, Chance and Probability. The NCERT Solutions For Class 7 Maths Chapter 3 Exercise 3.1 will help students find solutions to these questions in exercises.

Students will benefit from the material provided in the NCERT Solutions For Class 7 Maths Chapter 3 Exercise 3.1, when they progress to more difficult problems and during assessments. They will be better able to understand the question and determine which formula to employ while answering it. This will allow them to finish the exam faster. In this manner, they will be able to steer clear of confusion and give the question the right response. The right approach will make it simple for them to get the right responses. The NCERT Solutions For Class 7 Maths Chapter 3 Exercise 3.1, will give students a general understanding of these kinds of questions, which will help them perform well on tests. Students must therefore use the NCERT Solutions For Class 7 Maths Chapter 3 Exercise 3.1 to become familiar with the chapter, the format for answering, and to acquire a concrete understanding of the subjects. They will receive high marks as a result of this.

Exercise 3.1

The NCERT Solutions For Class 7 Maths Chapter 3 Exercise 3.1, give an overview of the chapter as well as the exercise. Chapter 3 Data Handling of Class 7 is centred around the theme of Statistics. This exercise is based on the topics of data collection, data organistaion, representation of values, arithmetic mean, and range. The first exercise comprises questions related to this chapter. The NCERT Solutions For Class 7 Maths Chapter 3 Exercise 3.1 will help students find answers to these questions and strengthen their knowledge. This exercise has 9 questions that help students understand the above-mentioned concepts. It will help students get better at solving these questions more accurately and faster in their exams. Some examples with similar concepts are also given in the NCERT textbook to help students understand the procedure of answering the questions. Solving and studying similar kinds of problems repeatedly will help them get better at those concepts and be aware of their mistakes.

Exercise 3.2

The NCERT Solutions For Class 7 Maths Chapter 3 Exercise 3.1 ,give an overview of the chapter as well as the exercise. The topics on which this exercise is based include mode, mode of large data, and median. The first exercise comprises questions related to this chapter. The NCERT Solutions For Class 7 Maths Chapter 3 Exercise 3.1, would help students find answers to these questions and strengthen their understanding. There are five questions in this exercise that will help students understand the concepts above. Students will be able to solve these questions more accurately and faster during their exams as a result of this course. Some examples with similar concepts are also given in the NCERT textbook to help students understand the procedure for answering the questions. Solving and studying similar kinds of problems repeatedly will help them get better at those concepts and be aware of their weak areas.

Exercise 3.3

The NCERT Solutions For Class 7 Maths Chapter 3 Exercise 3.1, give an overview of the chapter as well as the exercise. The topics on which this exercise is based include uses of bar graphs for different purposes, choosing a double bar graph, and drawing a double bar graph. The first exercise consists of questions related to this chapter. With the aid of NCERT Solutions For Class 7 Maths Chapter 3 Exercise 3.1, students will learn how to answer these questions. In this exercise, students will be asked to answer six questions related to the concepts discussed above. In their exams, students will be able to answer these questions more accurately and faster. Students can also find examples with similar concepts in the NCERT textbook to help them understand how to answer the questions.

Exercise 3.4

The NCERT Solutions For Class 7 Maths Chapter 3 Exercise 3.1, provide a comprehensive view of the chapter as well as the exercise. This exercise is based on the concepts of chance and probability, as well as what is meant by probability. There are questions related to this chapter in the first exercise. Using the NCERT Solutions For Class 7 Maths Chapter 3 Exercise 3.1, students will be able to find answers to these questions and will be able to strengthen their knowledge of the subject matter. Three questions are included in this exercise to help students understand the concepts described above. Students will be able to solve these questions more accurately and quickly in exams with the help of the reference materials for this exercise. In order to help students understand how to answer questions, the NCERT textbook also provides examples with similar concepts. Repeatedly solving and studying similar problems will help them understand those concepts and identify their weak areas.

Why Use Solved Class 11 Maths Exercises Solution NCERT

There are numerous advantages to using Extramarks to access NCERT Solutions for Class 7 Maths Chapter 3 Exercise 3.1. The experts at Extramarks compile these kinds of study materials for students. As a result, before being published on the Extramarks website, these responses are checked for inaccuracies and inconsistencies. The NCERT Solutions For Class 7 Maths Chapter 3 Exercise 3.1, will provide students with a summary of the activity and its contents in addition to providing them with the exact solutions. Students can use the NCERT Solutions For Class 7 Maths Chapter 3 Exercise 3.1 from Extramarks in order to study Statistics. Many students find it convenient because they can obtain the Solutions to Class 7 Maths Chapter 3 Exercise 3.1 via the website and the mobile application of Extramarks. The Extramarks NCERT Solutions For Class 7 Maths Chapter 3 Exercise 3.1, provide a precise technique of solution, specific solutions, and an explanation of the approaches used in the question as well as their importance in the annual examination for points. Another way Extramarks aids students is by providing study notes for all chapters and exercises, including NCERT Solutions For Class 7 Maths Chapter 3 Exercise 3.1. Furthermore, Extramarks provides NCERT solutions for all classes, including Class 12 and Class 11 NCERT solutions. An example of solutions provided by Extramarks are the NCERT Solutions For Class 7 Maths Chapter 3 Exercise 3.1.

The NCERT Solutions For Class 7 Maths Chapter 3 Exercise 3.1 assist students in their study of difficult questions in Class 7 Mathematics Chapter 3 Data Handling. These solutions allow students to go on to the next question after fixing their errors in the previous one. They can use these to alter their own answers or even come up with a more straightforward way to answer the question. The NCERT Solutions For Class 7 Maths Chapter 3 Exercise 3.1, help students by laying a firm conceptual foundation of ideas that they may then use to answer more challenging questions. The NCERT Solutions For Class 7 Maths Chapter 3 Exercise 3.1 can be used by students to study for annual examinations and entrance exams. In any case, students can improve their performance.

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What You Get in the NCERT Maths Class 7 Chapter 3 Exercise 3.1

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NCERT Solutions for Class 7

In addition to the NCERT Solutions For Class 7 Maths Chapter 3 Exercise 3.1, Extramarks also provides additional solutions for Mathematics as well as other subjects. After being checked for modifications and potential faults, solutions for Extramarks are published for students. It is ensured that the solutions provided are accurate, just like in the NCERT Solutions For Class 7 Maths Chapter 3 Exercise 3.1. These solutions are made available to students so they can enhance the quality of their own responses and performances. These answers, which have been engineered by the mentors at Extramarks, will help students get the grades they want. It is obvious that the solutions in the NCERT Solutions For Class 7 Maths Chapter 3 Exercise 3.1, are succinct and understandable to pupils learning the material for the first time. Students can only benefit from rigorously practising the NCERT Solutions For Class 7 Maths Chapter 3 Exercise 3.1 by becoming conscious of their weak areas as they work to solve the problems.

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Q.1

Organise the following marks in a class assessment, in at a bular form.

4 6 7 5 3 5 4 5 2 6
2 5 1 9 6 5 8 4 6 7

(i)Which number is the greatest?(ii) Which number is the lowest?(iii) What is the range of the data?(iv) Find the arithmetic mean.

Ans.

(i)9 (ii)1 (iii)Range=9-1= 8 (iv)Arithmeticmean= Sum of all observations Total number of observations = 100 20 = 5 MathType@MTEF@5@5@+= feaagKart1ev2aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbwvMCKf MBHbqeduuDJXwAKbYu51MyVXgaruWqVvNCPvMCG4uz3bqefqvATv2C G4uz3bIuV1wyUbqeeuuDJXwAKbsr4rNCHbGeaGqiVz0xg9vqqrpepC 0xbbL8F4rqqrFfpeea0xe9Lq=Jc9vqaqpepm0xbba9pwe9Q8fs0=yq aqpepae9pg0FirpepeKkFr0xfr=xfr=xb9adbaqaaeGaciGaaiaabe qaamaaeaqbaaGceaqabeaacaqGOaGaaeyAaiaabMcacaaMe8Uaaeyo aaqaaiaabIcacaqGPbGaaeyAaiaabMcacaaMe8UaaGymaaqaaiaacI cacaWGPbGaamyAaiaadMgacaGGPaGaaGjbVlaabkfacaqGHbGaaeOB aiaabEgacaqGLbGaaeypaiaabMdacaqGTaGaaeymaiabg2da9maaL4 babaGaaeioaaaaaeaacaGGOaGaamyAaiaadAhacaGGPaGaaGjbVlaa bgeacaqGYbGaaeyAaiaabshacaqGObGaaeyBaiaabwgacaqG0bGaae yAaiaabogacaaMe8UaaeyBaiaabwgacaqGHbGaaeOBaiaab2dadaWc aaqaaiaabofacaqG1bGaaeyBaiaabccacaqGVbGaaeOzaiaabccaca qGHbGaaeiBaiaabYgacaqGGaGaae4BaiaabkgacaqGZbGaaeyzaiaa bkhacaqG2bGaaeyyaiaabshacaqGPbGaae4Baiaab6gacaqGZbaaba Gaaeivaiaab+gacaqG0bGaaeyyaiaabYgacaqGGaGaaeOBaiaabwha caqGTbGaaeOyaiaabwgacaqGYbGaaeiiaiaab+gacaqGMbGaaeiiai aab+gacaqGIbGaae4CaiaabwgacaqGYbGaaeODaiaabggacaqG0bGa aeyAaiaab+gacaqGUbGaae4CaaaaaeaacaaMe8UaaGjbVlaaysW7ca aMe8UaaGjbVlaaysW7caaMe8UaaGjbVlaaysW7caaMe8UaaGjbVlaa ysW7caaMe8UaaGjbVlaaysW7caaMe8UaaGjbVlaaysW7caaMe8UaaG jbVlaaysW7caaMe8UaaGjbVlaaysW7cqGH9aqpdaWcaaqaaiaaigda caaIWaGaaGimaaqaaiaaikdacaaIWaaaaiabg2da9maaL4babaGaaG ynaaaaaaaa@C41C@

Q.2 Find the mean of the first five whole numbers.

Ans.

First five whole numbers are 0, 1, 2, 3 and 4Since Mean=Sum of all observationsTotal number of observationsSo, Mean = 0+1+2+3+45=102=5Thus, mean of first five whole number is 5.

Q.3 A cricket scores the following runs in eight innings:
58, 76, 40, 35, 46, 45, 0, 100.
Find the mean score.

Ans.

Since Mean=Sum of all observationsTotal number of observations So,Mean=58+76+40+35+46+45+0+1008=4008=50Thus, the mean score is 50

Q.4 Following table shows the points of each player scored in four game.

Player Game Game Game Game
A 14 16 10 10
B 0 8 6 4
C 8 11 Did not Play 13

Now answer the following questions:
(i) find the mean to determine A’ save range number of points scored per game.
(ii) To find mean number of points per game of C,
would you divide the total points by 3 or by 4? Why?
(iii) B played in all four games. How would you find the mean?
(iv) Who is the best performer?

Ans.

(i) Since Mean= Sum of all observations Total number of observations So,Mean= 14+16+10+10 4 = 50 4 = 12.5 Thus, As average number of points scored per game is 12.5 (ii) Since C played only 3 games, so to find the mean number of points per game for C,divide the total points by 3. (iii) Mean of B = 0+8+6+4 4 = 18 4 =4.5 (iv) Since, the mean of Ais better and bigger than B and C, so A is the best performer. MathType@MTEF@5@5@+= feaagKart1ev2aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbwvMCKf MBHbqeduuDJXwAKbYu51MyVXgaruWqVvNCPvMCG4uz3bqefqvATv2C G4uz3bIuV1wyUbqeeuuDJXwAKbsr4rNCHbGeaGqiVz0xg9vqqrpepC 0xbbL8F4rqqrFfpeea0xe9Lq=Jc9vqaqpepm0xbba9pwe9Q8fs0=yq aqpepae9pg0FirpepeKkFr0xfr=xfr=xb9adbaqaaeGaciGaaiaabe qaamaaeaqbaaGceaqabeaacaqGOaGaaeyAaiaabMcaaeaacaqGtbGa aeyAaiaab6gacaqGJbGaaeyzaiaabccacaqGnbGaaeyzaiaabggaca qGUbGaeyypa0ZaaSaaaeaacaqGtbGaaeyDaiaab2gacaqGGaGaae4B aiaabAgacaqGGaGaaeyyaiaabYgacaqGSbGaaeiiaiaab+gacaqGIb Gaae4CaiaabwgacaqGYbGaaeODaiaabggacaqG0bGaaeyAaiaab+ga caqGUbGaae4CaaqaaiaabsfacaqGVbGaaeiDaiaabggacaqGSbGaae iiaiaab6gacaqG1bGaaeyBaiaabkgacaqGLbGaaeOCaiaabccacaqG VbGaaeOzaiaabccacaqGVbGaaeOyaiaabohacaqGLbGaaeOCaiaabA hacaqGHbGaaeiDaiaabMgacaqGVbGaaeOBaiaabohaaaGaaeiiaaqa aiaabofacaqGVbGaaeilaiaaysW7caqGnbGaaeyzaiaabggacaqGUb Gaeyypa0ZaaSaaaeaacaaIXaGaaGinaiabgUcaRiaaigdacaaI2aGa ey4kaSIaaGymaiaaicdacqGHRaWkcaaIXaGaaGimaaqaaiaaisdaaa aabaGaeyypa0ZaaSaaaeaacaaI1aGaaGimaaqaaiaaisdaaaGaeyyp a0ZaauIhaeaacaaIXaGaaGOmaiaac6cacaaI1aaaaaqaaiaabsfaca qGObGaaeyDaiaabohacaqGSaGaaeiiaiaabgeacaGGzaIaae4Caiaa bccacaqGHbGaaeODaiaabwgacaqGYbGaaeyyaiaabEgacaqGLbGaae iiaiaab6gacaqG1bGaaeyBaiaabkgacaqGLbGaaeOCaiaabccacaqG VbGaaeOzaiaabccacaqGWbGaae4BaiaabMgacaqGUbGaaeiDaiaabo hacaqGGaGaae4CaiaabogacaqGVbGaaeOCaiaabwgacaqGKbGaaeii aiaabchacaqGLbGaaeOCaiaabccacaqGNbGaaeyyaiaab2gacaqGLb GaaeiiaiaabMgacaqGZbGaaeiiaiaabgdacaqGYaGaaeOlaiaabwda aeaacaqGOaGaaeyAaiaabMgacaqGPaaabaGaae4uaiaabMgacaqGUb Gaae4yaiaabwgacaqGGaGaae4qaiaabccacaqGWbGaaeiBaiaabgga caqG5bGaaeyzaiaabsgacaqGGaGaae4Baiaab6gacaqGSbGaaeyEai aabccacaqGZaGaaeiiaiaabEgacaqGHbGaaeyBaiaabwgacaqGZbGa aeilaiaabccacaqGZbGaae4BaiaabccacaqG0bGaae4Baiaabccaca qGMbGaaeyAaiaab6gacaqGKbGaaeiiaiaabshacaqGObGaaeyzaiaa bccacaqGTbGaaeyzaiaabggacaqGUbGaaeiiaiaab6gacaqG1bGaae yBaiaabkgacaqGLbGaaeOCaiaabccacaqGVbGaaeOzaaqaaiaabcha caqGVbGaaeyAaiaab6gacaqG0bGaae4CaiaabccacaqGWbGaaeyzai aabkhacaqGGaGaae4zaiaabggacaqGTbGaaeyzaiaabccacaqGMbGa ae4BaiaabkhacaqGGaGaae4qaiaacYcacaqGKbGaaeyAaiaabAhaca qGPbGaaeizaiaabwgacaqGGaGaaeiDaiaabIgacaqGLbGaaeiiaiaa bshacaqGVbGaaeiDaiaabggacaqGSbGaaeiiaiaabchacaqGVbGaae yAaiaab6gacaqG0bGaae4CaiaabccacaqGIbGaaeyEaiaabccacaqG ZaGaaeOlaaqaaiaabIcacaqGPbGaaeyAaiaabMgacaqGPaaabaGaae ytaiaabwgacaqGHbGaaeOBaiaabccacaqGVbGaaeOzaiaabccacaqG cbGaaeiiaiaab2dacaqGGaWaaSaaaeaacaaIWaGaey4kaSIaaGioai abgUcaRiaaiAdacqGHRaWkcaaI0aaabaGaaGinaaaacqGH9aqpdaWc aaqaaiaaigdacaaI4aaabaGaaGinaaaacqGH9aqpcaaI0aGaaiOlai aaiwdaaeaacaqGOaGaaeyAaiaabAhacaqGPaaabaGaae4uaiaabMga caqGUbGaae4yaiaabwgacaqGSaGaaeiiaiaabshacaqGObGaaeyzai aabccacaqGTbGaaeyzaiaabggacaqGUbGaaeiiaiaab+gacaqGMbGa aeiiaiaabgeacaaMb8UaaGjbVlaabMgacaqGZbGaaeiiaiaabkgaca qGLbGaaeiDaiaabshacaqGLbGaaeOCaiaabccacaqGHbGaaeOBaiaa bsgacaqGGaGaaeOyaiaabMgacaqGNbGaae4zaiaabwgacaqGYbGaae iiaiaabshacaqGObGaaeyyaiaab6gacaqGGaGaaeOqaiaabccacaqG HbGaaeOBaiaabsgacaqGGaGaae4qaiaabYcacaqGGaGaae4Caiaab+ gacaqGGaGaaeyqaiaabccacaqGPbGaae4CaaqaaiaabshacaqGObGa aeyzaiaabccacaqGIbGaaeyzaiaabohacaqG0bGaaeiiaiaabchaca qGLbGaaeOCaiaabAgacaqGVbGaaeOCaiaab2gacaqGLbGaaeOCaiaa b6caaaaa@8996@

Q.5 The marks (out of 100) obtained by a group of students in a science test are 85, 76, 90, 85, 39, 48, 56, 95, 81 and 75.
Find the :
(i) Highest and the lowest marks obtained by the students.
(ii) Range of the marks obtained.
(iii) Mean marks obtained by the group.

Ans.

(i) Clearly, the from the given data, the highest and the lowest marks are 95 and 39 respectively. (ii) Range=HighestLowest =9539=56 (iii)Mean= Sum of all observations Total number of observations = 85+76+90+58+39+48+56+95+81+75 10 = 70.3 MathType@MTEF@5@5@+= feaagKart1ev2aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbwvMCKf MBHbqeduuDJXwAKbYu51MyVXgaruWqVvNCPvMCG4uz3bqefqvATv2C G4uz3bIuV1wyUbqeeuuDJXwAKbsr4rNCHbGeaGqiVz0xg9vqqrpepC 0xbbL8F4rqqrFfpeea0xe9Lq=Jc9vqaqpepm0xbba9pwe9Q8fs0=yq aqpepae9pg0FirpepeKkFr0xfr=xfr=xb9adbaqaaeGaciGaaiaabe qaamaaeaqbaaGceaqabeaacaqGOaGaaeyAaiaabMcacaqGGaGaae4q aiaabYgacaqGLbGaaeyyaiaabkhacaqGSbGaaeyEaiaabYcacaqGGa GaaeiDaiaabIgacaqGLbGaaeiiaiaabAgacaqGYbGaae4Baiaab2ga caqGGaGaaeiDaiaabIgacaqGLbGaaeiiaiaabEgacaqGPbGaaeODai aabwgacaqGUbGaaeiiaiaabsgacaqGHbGaaeiDaiaabggacaqGSaGa aeiiaiaabshacaqGObGaaeyzaiaabccacaqGObGaaeyAaiaabEgaca qGObGaaeyzaiaabohacaqG0bGaaeiiaiaabggacaqGUbGaaeizaiaa bccacaqG0bGaaeiAaiaabwgacaqGGaGaaeiBaiaab+gacaqG3bGaae yzaiaabohacaqG0baabaGaaeyBaiaabggacaqGYbGaae4Aaiaaboha caqGGaGaaeyyaiaabkhacaqGLbGaaeiiaiaabMdacaqG1aGaaeiiai aabggacaqGUbGaaeizaiaabccacaqGZaGaaeyoaiaabccacaqGYbGa aeyzaiaabohacaqGWbGaaeyzaiaabogacaqG0bGaaeyAaiaabAhaca qGLbGaaeiBaiaabMhacaqGUaaabaGaaeikaiaabMgacaqGPbGaaeyk aiaabccacaqGsbGaaeyyaiaab6gacaqGNbGaaeyzaiabg2da9iaabI eacaqGPbGaae4zaiaabIgacaqGLbGaae4CaiaabshacqGHsislcaqG mbGaae4BaiaabEhacaqGLbGaae4CaiaabshaaeaacqGH9aqpcaaI5a GaaGynaiabgkHiTiaaiodacaaI5aGaeyypa0JaaGynaiaaiAdaaeaa caqGOaGaaeyAaiaabMgacaqGPbGaaeykaiaaygW7caaMe8Uaaeytai aabwgacaqGHbGaaeOBaiabg2da9iaaysW7daWcaaqaaiaabofacaqG 1bGaaeyBaiaabccacaqGVbGaaeOzaiaabccacaqGHbGaaeiBaiaabY gacaqGGaGaae4BaiaabkgacaqGZbGaaeyzaiaabkhacaqG2bGaaeyy aiaabshacaqGPbGaae4Baiaab6gacaqGZbaabaGaaeivaiaab+gaca qG0bGaaeyyaiaabYgacaqGGaGaaeOBaiaabwhacaqGTbGaaeOyaiaa bwgacaqGYbGaaeiiaiaab+gacaqGMbGaaeiiaiaab+gacaqGIbGaae 4CaiaabwgacaqGYbGaaeODaiaabggacaqG0bGaaeyAaiaab+gacaqG UbGaae4CaaaacaqGGaaabaGaaGjbVlaaysW7caaMe8UaaGjbVlaays W7caaMe8UaaGjbVlaaysW7caaMe8UaaGjbVlaaysW7caaMe8Uaeyyp a0ZaaSaaaeaacaaI4aGaaGynaiabgUcaRiaaiEdacaaI2aGaey4kaS IaaGyoaiaaicdacqGHRaWkcaaI1aGaaGioaiabgUcaRiaaiodacaaI 5aGaey4kaSIaaGinaiaaiIdacqGHRaWkcaaI1aGaaGOnaiabgUcaRi aaiMdacaaI1aGaey4kaSIaaGioaiaaigdacqGHRaWkcaaI3aGaaGyn aaqaaiaaigdacaaIWaaaaaqaaiaaysW7caaMe8UaaGjbVlaaysW7ca aMe8UaaGjbVlaaysW7caaMe8UaaGjbVlaaysW7caaMe8UaaGjbVlab g2da9maaL4babaGaaG4naiaaicdacaGGUaGaaG4maaaaaaaa@2CFB@

Q.6 The enrolment in a school during six consecutive years was as follows:
1555, 1670, 1750, 2013, 2540, 2820
Find the mean enrolment of the school for this period.

Ans.

Mean= Sum of all observations Total number of observations = 1555+1670+1750+2013+2540+2820 6 = 12348 6 = 2058 MathType@MTEF@5@5@+= feaagKart1ev2aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbwvMCKf MBHbqeduuDJXwAKbYu51MyVXgaruWqVvNCPvMCG4uz3bqefqvATv2C G4uz3bIuV1wyUbqeeuuDJXwAKbsr4rNCHbGeaGqiVz0xg9vqqrpepC 0xbbL8F4rqqrFfpeea0xe9Lq=Jc9vqaqpepm0xbba9pwe9Q8fs0=yq aqpepae9pg0FirpepeKkFr0xfr=xfr=xb9adbaqaaeGaciGaaiaabe qaamaaeaqbaaGceaabbeaacaqGnbGaaeyzaiaabggacaqGUbGaeyyp a0ZaaSaaaeaacaqGtbGaaeyDaiaab2gacaqGGaGaae4BaiaabAgaca qGGaGaaeyyaiaabYgacaqGSbGaaeiiaiaab+gacaqGIbGaae4Caiaa bwgacaqGYbGaaeODaiaabggacaqG0bGaaeyAaiaab+gacaqGUbGaae 4CaaqaaiaabsfacaqGVbGaaeiDaiaabggacaqGSbGaaeiiaiaab6ga caqG1bGaaeyBaiaabkgacaqGLbGaaeOCaiaabccacaqGVbGaaeOzai aabccacaqGVbGaaeOyaiaabohacaqGLbGaaeOCaiaabAhacaqGHbGa aeiDaiaabMgacaqGVbGaaeOBaiaabohaaaaabaGaeyypa0ZaaSaaae aacaaIXaGaaGynaiaaiwdacaaI1aGaey4kaSIaaGymaiaaiAdacaaI 3aGaaGimaiabgUcaRiaaigdacaaI3aGaaGynaiaaicdacqGHRaWkca aIYaGaaGimaiaaigdacaaIZaGaey4kaSIaaGOmaiaaiwdacaaI0aGa aGimaiabgUcaRiaaikdacaaI4aGaaGOmaiaaicdaaeaacaaI2aaaaa qaaiabg2da9maalaaabaGaaGymaiaaikdacaaIZaGaaGinaiaaiIda aeaacaaI2aaaaaqaaiabg2da9maaL4babaGaaGOmaiaaicdacaaI1a GaaGioaaaaaaaa@9170@

Q.7 The enrolment in a school during six consecutive years was as follows:
1555, 1670, 1750, 2013, 2540, 2820
Find the mean enrolment of the school for this period.

Ans.

Mean= Sum of all observations Total number of observations = 1555+1670+1750+2013+2540+2820 6 = 12348 6 = 2058 MathType@MTEF@5@5@+= feaagKart1ev2aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbwvMCKf MBHbqeduuDJXwAKbYu51MyVXgaruWqVvNCPvMCG4uz3bqefqvATv2C G4uz3bIuV1wyUbqeeuuDJXwAKbsr4rNCHbGeaGqiVz0xg9vqqrpepC 0xbbL8F4rqqrFfpeea0xe9Lq=Jc9vqaqpepm0xbba9pwe9Q8fs0=yq aqpepae9pg0FirpepeKkFr0xfr=xfr=xb9adbaqaaeGaciGaaiaabe qaamaaeaqbaaGceaabbeaacaqGnbGaaeyzaiaabggacaqGUbGaeyyp a0ZaaSaaaeaacaqGtbGaaeyDaiaab2gacaqGGaGaae4BaiaabAgaca qGGaGaaeyyaiaabYgacaqGSbGaaeiiaiaab+gacaqGIbGaae4Caiaa bwgacaqGYbGaaeODaiaabggacaqG0bGaaeyAaiaab+gacaqGUbGaae 4CaaqaaiaabsfacaqGVbGaaeiDaiaabggacaqGSbGaaeiiaiaab6ga caqG1bGaaeyBaiaabkgacaqGLbGaaeOCaiaabccacaqGVbGaaeOzai aabccacaqGVbGaaeOyaiaabohacaqGLbGaaeOCaiaabAhacaqGHbGa aeiDaiaabMgacaqGVbGaaeOBaiaabohaaaaabaGaeyypa0ZaaSaaae aacaaIXaGaaGynaiaaiwdacaaI1aGaey4kaSIaaGymaiaaiAdacaaI 3aGaaGimaiabgUcaRiaaigdacaaI3aGaaGynaiaaicdacqGHRaWkca aIYaGaaGimaiaaigdacaaIZaGaey4kaSIaaGOmaiaaiwdacaaI0aGa aGimaiabgUcaRiaaikdacaaI4aGaaGOmaiaaicdaaeaacaaI2aaaaa qaaiabg2da9maalaaabaGaaGymaiaaikdacaaIZaGaaGinaiaaiIda aeaacaaI2aaaaaqaaiabg2da9maaL4babaGaaGOmaiaaicdacaaI1a GaaGioaaaaaaaa@9170@

Q.8 The rain fall (in mm) in a city on 7 days of a certain week was recorded as follows:

Day Mon Tue Wed Thu Fri Sat Sun
Rainfall

(in mm)

0.0 12.2 2.1 0.0 20.5 5.5 1.0

(i) Find the range of the rainfall in the above data.
(
ii)
Find the mean rainfall for the week.

(iii) On how many days was the rainfall less than the mean rainfall.

 

 

Ans.

(i) Range=Highest-Lowest =20.5 mm0.0 mm= 20.5 mm (ii)Mean rainfall = 0.0+12.2+2.1+0.0+20.5+5.5+1.0 7 = 41.3 7 =5.9mm (iii)For five days(Monday, Wednesday, Thursday, Saturday and Sunday), rainfall was less than the mean rainfall. MathType@MTEF@5@5@+= feaagKart1ev2aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbwvMCKf MBHbqeduuDJXwAKbYu51MyVXgaruWqVvNCPvMCG4uz3bqefqvATv2C G4uz3bIuV1wyUbqeeuuDJXwAKbsr4rNCHbGeaGqiVz0xg9vqqrpepC 0xbbL8F4rqqrFfpeea0xe9Lq=Jc9vqaqpepm0xbba9pwe9Q8fs0=yq aqpepae9pg0FirpepeKkFr0xfr=xfr=xb9adbaqaaeGaciGaaiaabe qaamaaeaqbaaGceaqabeaacaqGOaGaaeyAaiaabMcacaqGGaGaaeOu aiaabggacaqGUbGaae4zaiaabwgacqGH9aqpcaqGibGaaeyAaiaabE gacaqGObGaaeyzaiaabohacaqG0bGaaeylaiaabYeacaqGVbGaae4D aiaabwgacaqGZbGaaeiDaaqaaiabg2da9iaaikdacaaIWaGaaiOlai aabwdacaqGGaGaaeyBaiaab2gacaGGTaGaaGimaiaac6cacaqGWaGa aeiiaiaab2gacaqGTbGaeyypa0ZaauIhaeaacaaIYaGaaGimaiaac6 cacaaI1aaaaiaaysW7caqGTbGaaeyBaaqaaiaabIcacaqGPbGaaeyA aiaabMcacaaMe8UaaeytaiaabwgacaqGHbGaaeOBaiaabccacaqGYb GaaeyyaiaabMgacaqGUbGaaeOzaiaabggacaqGSbGaaeiBaiaabcca cqGH9aqpcaqGGaWaaSaaaeaacaaIWaGaaiOlaiaaicdacqGHRaWkca aIXaGaaGOmaiaac6cacaaIYaGaey4kaSIaaGOmaiaac6cacaaIXaGa ey4kaSIaaGimaiaac6cacaaIWaGaey4kaSIaaGOmaiaaicdacaGGUa GaaGynaiabgUcaRiaaiwdacaGGUaGaaGynaiabgUcaRiaaigdacaGG UaGaaGimaaqaaiaaiEdaaaaabaGaaGjbVlaaysW7caaMe8UaaGjbVl aaysW7caaMe8UaaGjbVlaaysW7caaMe8UaaGjbVlaaysW7caaMe8Ua aGjbVlaaysW7caaMe8UaaGjbVlaaysW7caaMe8UaaGjbVlaaysW7ca aMe8Uaeyypa0ZaaSaaaeaacaaI0aGaaGymaiaac6cacaaIZaaabaGa aG4naaaacqGH9aqpcaaI1aGaaiOlaiaaiMdacaaMe8UaaeyBaiaab2 gaaeaacaqGOaGaaeyAaiaabMgacaqGPbGaaeykaiaaysW7caqGgbGa ae4BaiaabkhacaqGGaGaaeOzaiaabMgacaqG2bGaaeyzaiaabccaca qGKbGaaeyyaiaabMhacaqGZbGaaGjbVlaabIcacaqGnbGaae4Baiaa b6gacaqGKbGaaeyyaiaabMhacaqGSaGaaeiiaiaabEfacaqGLbGaae izaiaab6gacaqGLbGaae4CaiaabsgacaqGHbGaaeyEaiaabYcacaqG GaGaaeivaiaabIgacaqG1bGaaeOCaiaabohacaqGKbGaaeyyaiaabM hacaqGSaGaaeiiaiaabofacaqGHbGaaeiDaiaabwhacaqGYbGaaeiz aiaabggacaqG5baabaGaaGjbVlaaysW7caaMe8UaaGjbVlaabccaca qGHbGaaeOBaiaabsgacaqGGaGaae4uaiaabwhacaqGUbGaaeizaiaa bggacaqG5bGaaeykaiaabYcacaqGGaGaaeOCaiaabggacaqGPbGaae OBaiaabAgacaqGHbGaaeiBaiaabYgacaqGGaGaae4DaiaabggacaqG ZbGaaeiiaiaabYgacaqGLbGaae4CaiaabohacaqGGaGaaeiDaiaabI gacaqGHbGaaeOBaiaabccacaqG0bGaaeiAaiaabwgacaqGGaGaaeyB aiaabwgacaqGHbGaaeOBaiaabccacaqGYbGaaeyyaiaabMgacaqGUb GaaeOzaiaabggacaqGSbGaaeiBaiaab6caaaaa@2482@

Q.9

The heights of 10 girls were measured in cm and theresults are as follows:135,150,139,128,151,132,146,149,143,141iWhat is the height of the tallest girl?iiWhat is the height of the shortest girl?iiiWhat is the range of the data?ivWhat is the mean height of the girls?vHow many girls have heights more than the mean

Ans.

(i) The height of the tallest girl is 151 cm. (ii) The height of the shortest girl is 128. (iii) Range=HighestLowest=( 151128 )cm= 23cm (iv) Mean height = 135+150+139+128+151+132+146+149+143+141 10 = 1414 10 = 141.4cm Thus, five girls have more height than the mean height. MathType@MTEF@5@5@+= feaagKart1ev2aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbwvMCKf MBHbqeduuDJXwAKbYu51MyVXgaruWqVvNCPvMCG4uz3bqefqvATv2C G4uz3bIuV1wyUbqeeuuDJXwAKbsr4rNCHbGeaGqiVz0xg9vqqrpepC 0xbbL8F4rqqrFfpeea0xe9Lq=Jc9vqaqpepm0xbba9pwe9Q8fs0=yq aqpepae9pg0FirpepeKkFr0xfr=xfr=xb9adbaqaaeGaciGaaiaabe qaamaaeaqbaaGceaqabeaacaqGOaGaaeyAaiaabMcacaqGGaGaaeiv aiaabIgacaqGLbGaaeiiaiaabIgacaqGLbGaaeyAaiaabEgacaqGOb GaaeiDaiaabccacaqGVbGaaeOzaiaabccacaqG0bGaaeiAaiaabwga caqGGaGaaeiDaiaabggacaqGSbGaaeiBaiaabwgacaqGZbGaaeiDai aabccacaqGNbGaaeyAaiaabkhacaqGSbGaaeiiaiaabMgacaqGZbGa aeiiaiaabgdacaqG1aGaaeymaiaabccacaqGJbGaaeyBaiaab6caae aacaqGOaGaaeyAaiaabMgacaqGPaGaaeiiaiaabsfacaqGObGaaeyz aiaabccacaqGObGaaeyzaiaabMgacaqGNbGaaeiAaiaabshacaqGGa Gaae4BaiaabAgacaqGGaGaaeiDaiaabIgacaqGLbGaaeiiaiaaboha caqGObGaae4BaiaabkhacaqG0bGaaeyzaiaabohacaqG0bGaaeiiai aabEgacaqGPbGaaeOCaiaabYgacaqGGaGaaeyAaiaabohacaqGGaGa aeymaiaabkdacaqG4aGaaeOlaaqaaiaabIcacaqGPbGaaeyAaiaabM gacaqGPaGaaeiiaiaabkfacaqGHbGaaeOBaiaabEgacaqGLbGaeyyp a0JaaeisaiaabMgacaqGNbGaaeiAaiaabwgacaqGZbGaaeiDaiabgk HiTiaabYeacaqGVbGaae4DaiaabwgacaqGZbGaaeiDaiabg2da9maa bmaabaGaaGymaiaaiwdacaaIXaGaeyOeI0IaaGymaiaaikdacaaI4a aacaGLOaGaayzkaaGaae4yaiaab2gacqGH9aqpdaqjEaqaaiaaikda caaIZaGaaGjbVlaabogacaqGTbaaaaqaaiaabIcacaqGPbGaaeODai aabMcacaqGGaGaaeytaiaabwgacaqGHbGaaeOBaiaabccacaqGObGa aeyzaiaabMgacaqGNbGaaeiAaiaabshaaeaacqGH9aqpdaWcaaqaai aaigdacaaIZaGaaGynaiabgUcaRiaaigdacaaI1aGaaGimaiabgUca RiaaigdacaaIZaGaaGyoaiabgUcaRiaaigdacaaIYaGaaGioaiabgU caRiaaigdacaaI1aGaaGymaiabgUcaRiaaigdacaaIZaGaaGOmaiab gUcaRiaaigdacaaI0aGaaGOnaiabgUcaRiaaigdacaaI0aGaaGyoai abgUcaRiaaigdacaaI0aGaaG4maiabgUcaRiaaigdacaaI0aGaaGym aaqaaiaaigdacaaIWaaaaaqaaiabg2da9maalaaabaGaaGymaiaais dacaaIXaGaaGinaaqaaiaaigdacaaIWaaaaaqaaiabg2da9maaL4ba baGaaGymaiaaisdacaaIXaGaaiOlaiaaisdacaaMe8Uaae4yaiaab2 gaaaaabaGaaeivaiaabIgacaqG1bGaae4CaiaabYcacaqGGaGaaeOz aiaabMgacaqG2bGaaeyzaiaabccacaqGNbGaaeyAaiaabkhacaqGSb Gaae4CaiaabccacaqGObGaaeyyaiaabAhacaqGLbGaaeiiaiaab2ga caqGVbGaaeOCaiaabwgacaqGGaGaaeiAaiaabwgacaqGPbGaae4zai aabIgacaqG0bGaaeiiaiaabshacaqGObGaaeyyaiaab6gacaqGGaGa aeiDaiaabIgacaqGLbGaaeiiaiaab2gacaqGLbGaaeyyaiaab6gaca qGGaGaaeiAaiaabwgacaqGPbGaae4zaiaabIgacaqG0bGaaeOlaaaa aa@1B15@

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FAQs (Frequently Asked Questions)

1. Where can students obtain the NCERT Solutions For Class 7 Maths Chapter 3 Exercise 3.1?

On the Extramarks website and Learning App, students studying Mathematics in Class 7 can access the NCERT Solutions For Class 7 Maths Chapter 3 Exercise 3.1. They have been simplified and made more engaging for pupils in schools, especially those that are associated with the CBSE board, to make learning and understanding solutions easier. The NCERT Solutions For Class 7 Maths Chapter 3 Exercise 3.1 are one of the many NCERT solutions for Class 10 available on Extramarks. In relation to a number of exams, such as the TOEFL, SATs, Olympiad, Board Exam, JEE, NEET, CUET, etc. Extramarks provides study aids. On Extramarks, students can look for study materials for whatever exam they are preparing for. Along with answers to the exercises’ questions from other chapters and topics, Extramarks also has the NCERT Solutions For Class 7 Maths Chapter 3 Exercise 3.1. Highly qualified educators have engineered the NCERT Solutions For Class 7 Maths Chapter 3 Exercise 3.1 to help students with any queries they might have.

2. Are students helped by the NCERT Solutions For Class 7 Maths Chapter 3 Exercise 3.1?

For students preparing for Class 7 annual exams, the NCERT Solutions For Class 7 Maths Chapter 3 Exercise 3.1 are regarded as helpful. With their correctness and effectiveness, the NCERT Solutions For Class 7 Maths Chapter 3 Exercise 3.1 will assist students in resolving their questions. Students should use the NCERT solutions provided by Extramarks to improve their exam results. The NCERT Solutions For Class 7 Maths Chapter 3 Exercise 3.1 will help improve students’ grades. They will be able to comprehend the chapter more effectively as a result. It will assist students to develop an interest in the topic and field and enable them to make more informed decisions regarding their future. By using NCERT Solutions For Class 7 Maths Chapter 3 Exercise 3.1, students can learn a lot about the Class 7 Maths Chapter 3 Exercise 3.1.

3. Does Extramarks have any resources for Class 7 students that are similar to the NCERT Solutions For Class 7 Maths Chapter 3 Exercise 3.1?

Extramarks provides content like NCERT Solutions For Class 7 Maths Chapter 3 Exercise 3.1 to make it easier for students to obtain their education for Class 7. The NCERT Solutions For Class 7 Maths Chapter 3 Exercise 3.1 are a great resource for revision before exams because these are simple for students to skim through. For Class 7 subjects including English, Hindi, Mathematics, Science, Social Science, and more, Extramarks offers NCERT solutions. Students can access all of these reference materials, including NCERT solutions, study notes, key ideas, and questions, through the Extramarks portal.

4. How could students study for their board exams with the NCERT Solutions For Class 7 Maths Chapter 3 Exercise 3.1?

Students can use the NCERT Solutions For Class 7 Maths Chapter 3 Exercise 3.1 to understand how to write and react to questions during board exams. When students are confused with regard to any questions in the NCERT textbooks, it is beneficial to practice using the NCERT Solutions For Class 7 Maths Chapter 3 Exercise 3.1 since these will clear up questions more quickly. With the help of the NCERT Solutions For Class 7 Maths Chapter 3 Exercise 3.1, students may move past their errors in answering a question and move on to the next one.

5. Why do students find it difficult to answer problems when studying Data Handling from the NCERT Class 7 Maths Chapter 3 Exercise 3.1?

Problems are frequently encountered when attempting to answer these topics in Mathematics. It is difficult to properly understand and apply the formulas accurately on the first try. Students can ask for help from their friends, teachers, and the NCERT Solutions For Class 7 Maths Chapter 3 Exercise 3.1 to advance in their studies. If any uncertainty arises, they can interact with mentors of Extramarks for help. It provides training for entrance tests for numerous colleges and universities as well as preparation for board exams. Extramarks offers workshops to help people who are confused. The NCERT Solutions For Class 7 Maths Chapter 3 Exercise 3.1 can be evaluated by students. As a consequence of their diligent study efforts, students can reflect on and refer to the NCERT Solutions For Class 7 Maths Chapter 3 Exercise 3.1 before the exam. Students can use these solutions to review shortly before an exam and to proofread their own work.