NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals (EX 2.4) Exercise 2.4

Students need to understand the topics of Mathematics thoroughly, as it is a purely conceptual subject. Fractions and Decimals are the topic of Chapter 2 of Class 7 Mathematics. The concepts and calculations of this chapter can be understood properly with practice and proper guidance. Real-life concepts like the conversion of units such as Centimetre to Metre or Kilometre and Gram to Kilogram are explained in this chapter. The chapter includes- Introduction, Multiplication, and Division of Fractions, Multiplication, and Division of Decimal Numbers etc. The chapter contains seven exercises in all and several interesting concepts. Students learn about Equivalent Fractions, Addition, and Multiplication of Fractions, Rearrangement of Fractions in Ascending and Descending Order, Multiplication of a Fraction with a Whole Number and Conversion of an Improper Fraction into a Mixed Fraction. Apart from this, it includes a comparison between fractions, different place values of a decimal number, a comparison between decimal numbers, and many more concepts. With proper practice, students can grasp the concepts of this chapter and learn it with interest. By utilising all the resources provided by Extramarks, they can make their learning experience comprehensive and effortless and excel in their examinations.

There are no solutions provided for the exercises in NCERT Textbooks. Students can understand the questions given in the NCERT Textbook with the help of clear solutions and approach to each question provided by the Extramarks’ Class 7 Maths Chapter 2 Exercise 2.4 Solutions. NCERT textbook forms the basis for the concepts of any Mathematics chapter. The Class 7 Maths Exercise 2.4 should be practised thoroughly by the learners.

In CBSE schools, only the NCERT curriculum is used. NCERT textbooks are written by educators who are highly experienced and experts in their fields. As a result, these textbooks are excellent resources for students to understand the fundamentals. With Extramarks, they can access authentic NCERT solutions for all classes and subjects, such as the Class 7 Maths Chapter 2 Exercise 2.4. Along with the NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.4, Extramarks offers students a variety of learning modules that enable them to learn comprehensively and perform effectively. Apart from these solutions, Extramarks provides various learning modules such as K-12 Study Material that provides students with a convenient and comprehensive way that helps them succeed in any examinations. Furthermore, Extramarks help learners to assess themselves and track their academic progress with a Detailed Performance Report. Educators provide live assistance to young minds through Extramarks’ Live Doubt Solving Classes. Thus, learners are able to resolve their queries so that they can perform effectively in examinations. If students have any doubts regarding the NCERT textbook questions for Mathematics Chapter 2, they can refer to the NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.4. They can practice chapter-wise worksheets, answer unlimited practice questions, and participate in interactive activities in order to achieve proficiency in all subjects. Students can also benefit from visual learning through the Learning App to improve their understanding of the subject’s curriculum. Due to Extramarks’ visuals and animations, students do not find learning monotonous. With Extramarks, they gain access to highly qualified and experienced educators who are experts in their fields and can offer learners the best guidance possible. For Class 7 students, Mathematics is one of the more challenging subjects. The NCERT textbook is a significant resource for them to build solid fundamentals in Mathematics. Therefore, to be able to achieve good grades in the subject, students should be thorough with the NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.4.

NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals (EX 2.4) Exercise 2.4

Students can download the NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.4, provided by Extramarks in PDF format. They can easily access and download the solutions, making it easy to review them whenever they want. These solutions are curated by expert educators at Extramarks and are properly detailed in a step-by-step approach. That is why Extramarks recommends that students review these solutions carefully before the examinations. The NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.4, help students understand the concept and logic behind every answer. They are excellent preparation tools for Class 7 Mathematics examinations.

Going through the NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.4, helps students make their basics of the chapter stronger and also provides them with a steady calculation speed. With the assistance of Extramarks learning tools, such as K12 Study Materials, Complete Syllabus Coverage, Engaging Media Content, Curriculum Mapped Learning, and much more, students can learn systematically and become more engaged in their studies. Along with these solutions, the website also provides learners with NCERT solutions for all academic sessions and subjects. They can learn, practice, and get their doubts cleared with the help of Extramarks. Students should follow up with the NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.4, as they are designed by the subject experts at Extramarks and ensure a smooth learning experience for them. Hence, if they want to understand the concepts of the chapter, they should review Extramarks’ NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.4.

Students can easily find these solutions online, and there are multiple portals that provide them with these solutions. They should, however, verify the credibility of these sources because all the learning platforms are not trustworthy. Learners can find reliable study material at Extramarks. Apart from the NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.4, it has multiple practice modules, such as sample papers, past years’ papers, and question banks for students. The curriculum-based study material has been compiled by the in-house experts of Extramarks. Fact-checked and accurate information has been provided to students by Extramarks. By studying sample papers and past year’s papers provided by Extramarks, learners can also get an idea of the examination pattern. Since the same type of question has appeared repeatedly in the examinations, it provides young minds with an understanding of the types of questions that can appear in front of them. Students can learn how to write answers by practising solved sample papers, which will enable them to achieve maximum marks in the subject. In addition to providing students with an exact blueprint of the question paper, sample papers can also be used to write answers to the questions in the examination. For quick revisions, they are a great tool. Students are recommended to review sample papers and past years’ papers prior to examinations.

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Access NCERT Solutions for Class 7 Maths Chapter 2 – Fractions and Decimals

Students can easily download the NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.4, from the Extramarks website. These solutions are compiled in very straightforward language so that they can comprehend them without any difficulty. When it comes to Mathematics, it all comes down to critical thinking. A number of skills are required to succeed in the subject, including critical thinking skills, problem-solving skills, and much more. To be able to perform well in Mathematics, students must practice NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.4, meticulously. It is also essential that learners possess clear and basic concepts in order to score higher marks. Therefore, Extramarks provides them with the NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.4. Although there is only one NCERT textbook in Class 7 Mathematics, the syllabus of the curriculum is extensive, so students must work hard to become familiar with every chapter of the syllabus. The key to clearing students’ basics is learning NCERT textbook questions by heart. As Chapter 2 contains many new concepts, it can be intimidating for learners. They can find the NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.4, on the Extramarks website, which provides step-by-step explanations and detailed answers that greatly enhance their conceptual understanding. A team of Extramarks subject experts has cross-checked and curated these answers. The Extramarks website provides students with the NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.4, which they can download and practice in order to achieve maximum marks in their examinations.

The NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.4, are used as the primary source for teaching the subject in CBSE schools. They provide students with valuable resources for clarifying their concepts. Several schools heavily rely on NCERT textbooks for teaching, due to the fact that examinations are largely based on NCERT fundamentals. The NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.4 provided by the Extramarks website can be easily accessed from a variety of devices. These solutions are curated in a very simple language in order to facilitate learning for students. Students can find it easy to learn the chapter “Fractions and Decimals” as they have gone through the concepts of the topic in the previous classes. However, the difficulty level of the chapter has increased in Class 7. The NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.4, are available on the Extramarks website and offer detailed explanations and answers that enhance students’ conceptual understanding. Learners should practice the NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.4, thoroughly in order to have a deeper understanding of the concepts of the chapter.

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Fraction and Decimals Class 7 Exercise 2.4 – In a Nutshell

Practising the NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.4, is very essential for students before appearing in the Class 7 Mathematics examination. It helps them keep track of their academic progress and preparation level. Furthermore, practising the NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.4, not only helps students perform better in the examinations but also helps them decide if they want to opt for Mathematics for their higher classes. These solutions contain all the key concepts and important questions of the chapter that are likely to appear in the examinations. As an e-learning portal, Extramarks has always provided young learners with all the resources they need to learn, practice, and excel in their studies. Therefore, Extramarks provides students with the NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.4 so that they can prepare well for their examinations. The solutions provided by the Extramarks provide students with a comprehensive revision schedule. Therefore, these solutions are very essential tools for the revision and deeper understanding of the chapter’s concepts. These solutions are essential for those who have problems understanding the concepts and questions of this chapter. Furthermore, along with practising the NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.4, students can go through the entire exercises for every chapter. This helps learners to ensure that they do not miss any important topics for examinations.

Class 7th Maths Chapter 2 Exercise 2.4 – Other exercises

The NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.4, provided by Extramarks include precise answers in a step-by-step approach to all the questions of the textbook. Students use these solutions for a deeper understanding of the chapter’s concepts and for improving their problem-solving abilities. They must thoroughly review the NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.4 in order to easily solve all the difficult problems related to the concepts of the chapter. Along with helping learners form a firm understanding of the basics of the chapter, these solutions guide them to learn different approaches to solving the questions. The NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.4, also helps students to improve their preparation for the subject of Mathematics. This helps them apply this chapter’s concepts to real-life scenarios. These solutions also provide them with an overview of the chapter. Students can use these solutions to review all the key points of the chapter quickly. To be able to perform well in Mathematics Class 7 examinations, Extramarks recommends them to thoroughly solve and practice the NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.4. Extramarks is dedicated to helping students succeed academically. Consequently, NCERT Class 7 Maths Chapter 2 Exercise 2.4 provides them with these solutions, along with other study materials.

NCERT Solutions for Class 7

Many students in Class 7 utilise the NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.4 solutions to prepare for their examinations. By practising these solutions, students gain a strong understanding of the concepts of the chapter and may solve any complicated problem during the examination. In addition to the NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.4, students of Class 7 should practice a variety of questions prior to their examinations. NCERT textbooks contain only a few questions explaining concepts, but practising those questions thoroughly is essential for a deeper understanding. Extramarks provides students with various learning modules and study materials to help them achieve academic success. The NCERT Solutions For Class 7 Maths Chapter 2 Exercise 2.4 is a paradigm of one such learning tool where young learners can understand and learn about the concepts and score the maximum marks in their examinations.

Q.1

Find:(i)12÷34 (ii)14÷56 (iii)73(iv)83 (v)3÷213 (vi)5÷347

Ans.

(i) 12÷34=12×43=483=16(ii) 14÷56=14×65=845=1645(iii) 8÷73=8×37=247=337(iv) 4÷83=4×383=32=112(v) 3÷213=3÷73=3×37=97=127(vi) 5÷347=5÷257=5×7257=75=125

Q.2

Find the reciprocal of each of the following fractions. Classify the reciprocals as properfractions, improper fractions and whole numbers.(i)37 (ii)58 (iii)97 (iv)​ 65(v)​ 127 (vi)18 (vii)111

Ans.

(i)37Reciprocal of 37is73 and it is an improper fraction.(ii)58Reciprocal of 58is85 and it is an improper fraction(iii) 97Reciprocal of 97is79 and it is an proper fraction(iv)​ 65Reciprocal of 65is56 and it is an proper fraction(v)127Reciprocal of 127is712 and it is an proper fraction(vi)18Reciprocal of 18is81 and it is an whole fraction(vii)111Reciprocal of 111is11 and it is a whole number.

Q.3

Find:(i)73÷2 (ii)49÷5 (iii)613÷7(iv)413÷3 (v)312÷4 (vi)437÷7

Ans.

(i) 7 3 ÷2= 7 3 × 1 2 = 7 6 = 1 1 6 (ii) 4 9 ÷5= 4 9 × 1 5 = 4 45 (iii) 6 13 ÷7= 6 13 × 1 7 = 6 91 (iv)4 1 3 ÷3= 13 3 × 1 3 = 13 9 = 1 4 9 (v)3 1 2 ÷4= 7 2 × 1 4 = 7 8 (vi)4 3 7 ÷7= 31 7 × 1 7 = 31 49 MathType@MTEF@5@5@+= feaagKart1ev2aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbwvMCKf MBHbqeduuDJXwAKbYu51MyVXgaruWqVvNCPvMCG4uz3bqefqvATv2C G4uz3bIuV1wyUbqeeuuDJXwAKbsr4rNCHbGeaGqiVz0xg9vqqrpepC 0xbbL8F4rqqrFfpeea0xe9Lq=Jc9vqaqpepm0xbba9pwe9Q8fs0=yq aqpepae9pg0FirpepeKkFr0xfr=xfr=xb9adbaqaaeGaciGaaiaabe qaamaaeaqbaaGceaqabeaacaGGOaGaamyAaiaacMcacaaMe8+aaSaa aeaacaaI3aaabaGaaG4maaaacqGH3daUcaaIYaGaeyypa0ZaaSaaae aacaaI3aaabaGaaG4maaaacqGHxdaTdaWcaaqaaiaaigdaaeaacaaI Yaaaaiabg2da9maalaaabaGaaG4naaqaaiaaiAdaaaGaeyypa0Zaau IhaeaacaaIXaWaaSaaaeaacaaIXaaabaGaaGOnaaaaaaaabaGaaiik aiaadMgacaWGPbGaaiykaiaaysW7daWcaaqaaiaaisdaaeaacaaI5a aaaiabgEpa4kaaiwdacqGH9aqpdaWcaaqaaiaaisdaaeaacaaI5aaa aiabgEna0oaalaaabaGaaGymaaqaaiaaiwdaaaGaeyypa0ZaauIhae aadaWcaaqaaiaaisdaaeaacaaI0aGaaGynaaaaaaaabaGaaiikaiaa dMgacaWGPbGaamyAaiaacMcacaaMe8+aaSaaaeaacaaI2aaabaGaaG ymaiaaiodaaaGaey49aGRaaG4naiabg2da9maalaaabaGaaGOnaaqa aiaaigdacaaIZaaaaiabgEna0oaalaaabaGaaGymaaqaaiaaiEdaaa Gaeyypa0ZaauIhaeaadaWcaaqaaiaaiAdaaeaacaaI5aGaaGymaaaa aaaabaGaaiikaiaadMgacaWG2bGaaiykaiaaysW7caaI0aWaaSaaae aacaaIXaaabaGaaG4maaaacqGH3daUcaaIZaGaeyypa0ZaaSaaaeaa caaIXaGaaG4maaqaaiaaiodaaaGaey41aq7aaSaaaeaacaaIXaaaba GaaG4maaaacqGH9aqpdaWcaaqaaiaaigdacaaIZaaabaGaaGyoaaaa cqGH9aqpdaqjEaqaaiaaigdadaWcaaqaaiaaisdaaeaacaaI5aaaaa aaaeaacaGGOaGaamODaiaacMcacaaMe8UaaG4mamaalaaabaGaaGym aaqaaiaaikdaaaGaey49aGRaaGinaiabg2da9maalaaabaGaaG4naa qaaiaaikdaaaGaey41aq7aaSaaaeaacaaIXaaabaGaaGinaaaacqGH 9aqpdaqjEaqaamaalaaabaGaaG4naaqaaiaaiIdaaaaaaaqaaiaacI cacaWG2bGaamyAaiaacMcacaaMe8UaaGinamaalaaabaGaaG4maaqa aiaaiEdaaaGaey49aGRaaG4naiabg2da9maalaaabaGaaG4maiaaig daaeaacaaI3aaaaiabgEna0oaalaaabaGaaGymaaqaaiaaiEdaaaGa eyypa0ZaauIhaeaadaWcaaqaaiaaiodacaaIXaaabaGaaGinaiaaiM daaaaaaaaaaa@BA0D@

Q.4

Find (i) 2 5 ÷ 1 2 (ii) 4 9 ÷ 2 3 (iii) 3 7 ÷ 8 7 (iv)2 1 3 ÷ 3 5 (v)3 1 2 ÷ 8 3 (vi) 2 5 ÷1 1 2 (vii)3 1 5 ÷1 2 3 (viii)2 1 5 ÷1 1 5 MathType@MTEF@5@5@+= feaagKart1ev2aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbwvMCKf MBHbqeduuDJXwAKbYu51MyVXgaruWqVvNCPvMCG4uz3bqefqvATv2C G4uz3bIuV1wyUbqeeuuDJXwAKbsr4rNCHbGeaGqiVz0xg9vqqrpepC 0xbbL8F4rqqrFfpeea0xe9Lq=Jc9vqaqpepm0xbba9pwe9Q8fs0=yq aqpepae9pg0FirpepeKkFr0xfr=xfr=xb9adbaqaaeGaciGaaiaabe qaamaaeaqbaaGceaqabeaacaqGgbGaaeyAaiaab6gacaqGKbaabaGa aiikaiaadMgacaGGPaGaaGjbVpaalaaabaGaaGOmaaqaaiaaiwdaaa Gaey49aG7aaSaaaeaacaaIXaaabaGaaGOmaaaacaWLjaaabaGaaiik aiaadMgacaWGPbGaaiykaiaaygW7caaMe8+aaSaaaeaacaaI0aaaba GaaGyoaaaacqGH3daUdaWcaaqaaiaaikdaaeaacaaIZaaaaiaaxMaa aeaacaGGOaGaamyAaiaadMgacaWGPbGaaiykaiaaysW7daWcaaqaai aaiodaaeaacaaI3aaaaiabgEpa4oaalaaabaGaaGioaaqaaiaaiEda aaaabaGaaiikaiaadMgacaWG2bGaaiykaiaaysW7caaIYaWaaSaaae aacaaIXaaabaGaaG4maaaacqGH3daUdaWcaaqaaiaaiodaaeaacaaI 1aaaaaqaaiaacIcacaWG2bGaaiykaiaaysW7caaIZaWaaSaaaeaaca aIXaaabaGaaGOmaaaacqGH3daUdaWcaaqaaiaaiIdaaeaacaaIZaaa aaqaaiaacIcacaWG2bGaamyAaiaacMcacaaMe8+aaSaaaeaacaaIYa aabaGaaGynaaaacqGH3daUcaaIXaWaaSaaaeaacaaIXaaabaGaaGOm aaaaaeaacaGGOaGaamODaiaadMgacaWGPbGaaiykaiaaysW7caaIZa WaaSaaaeaacaaIXaaabaGaaGynaaaacqGH3daUcaaIXaWaaSaaaeaa caaIYaaabaGaaG4maaaaaeaacaGGOaGaamODaiaadMgacaWGPbGaam yAaiaacMcacaaMe8UaaGOmamaalaaabaGaaGymaaqaaiaaiwdaaaGa ey49aGRaaGymamaalaaabaGaaGymaaqaaiaaiwdaaaaaaaa@9B80@

Ans.

(i) 2 5 ÷ 1 2 = 2 5 × 2 1 = 4 5 (ii) 4 9 ÷ 2 3 = 4 9 × 3 2 = ( 2× 2 ) ( 3× 3 ) × 3 2 = 2 3 (iii) 3 7 ÷ 8 7 = 3 7 × 7 8 = 3 8 (iv)2 1 3 ÷ 3 5 = 7 3 × 5 3 = 35 9 = 3 8 9 (v)3 1 2 ÷ 8 3 = 7 2 × 3 8 = 21 16 = 1 5 16 (vi) 2 5 ÷1 1 2 = 2 5 ÷ 3 2 = 2 5 × 2 3 = 4 15 (vii)3 1 5 ÷1 2 3 = 16 5 ÷ 5 3 = 16 5 × 3 5 = 48 25 = 1 23 25 (viii)2 1 5 ÷1 1 5 = 11 5 ÷ 6 5 = 11 5 × 5 6 = 11 6 = 1 5 6 MathType@MTEF@5@5@+= feaagKart1ev2aaatCvAUfeBSjuyZL2yd9gzLbvyNv2CaerbwvMCKf MBHbqeduuDJXwAKbYu51MyVXgaruWqVvNCPvMCG4uz3bqefqvATv2C G4uz3bIuV1wyUbqeeuuDJXwAKbsr4rNCHbGeaGqiVz0xg9vqqrpepC 0xbbL8F4rqqrFfpeea0xe9Lq=Jc9vqaqpepm0xbba9pwe9Q8fs0=yq aqpepae9pg0FirpepeKkFr0xfr=xfr=xb9adbaqaaeGaciGaaiaabe qaamaaeaqbaaGceaqabeaacaGGOaGaamyAaiaacMcacaaMe8+aaSaa aeaacaaIYaaabaGaaGynaaaacqGH3daUdaWcaaqaaiaaigdaaeaaca aIYaaaaiabg2da9maalaaabaGaaGOmaaqaaiaaiwdaaaGaey41aq7a aSaaaeaacaaIYaaabaGaaGymaaaacqGH9aqpdaqjEaqaamaalaaaba GaaGinaaqaaiaaiwdaaaaaaaqaaiaacIcacaWGPbGaamyAaiaacMca caaMe8+aaSaaaeaacaaI0aaabaGaaGyoaaaacqGH3daUdaWcaaqaai aaikdaaeaacaaIZaaaaiabg2da9maalaaabaGaaGinaaqaaiaaiMda aaGaey41aq7aaSaaaeaacaaIZaaabaGaaGOmaaaacqGH9aqpdaWcaa qaamaabmaabaGaaGOmaiabgEna0kqaikdagaGfaaGaayjkaiaawMca aaqaamaabmaabaGaaG4maiabgEna0kqaiodagaGfaaGaayjkaiaawM caaaaacqGHxdaTdaWcaaqaaiqaiodagaGfaaqaaiqaikdagaGfaaaa cqGH9aqpdaqjEaqaamaalaaabaGaaGOmaaqaaiaaiodaaaaaaaqaai aacIcacaWGPbGaamyAaiaadMgacaGGPaGaaGjbVpaalaaabaGaaG4m aaqaaiaaiEdaaaGaey49aG7aaSaaaeaacaaI4aaabaGaaG4naaaacq GH9aqpdaWcaaqaaiaaiodaaeaaceaI3aGbaybaaaGaey41aq7aaSaa aeaaceaI3aGbaybaaeaacaaI4aaaaiabg2da9maaL4babaWaaSaaae aacaaIZaaabaGaaGioaaaaaaaabaGaaiikaiaadMgacaWG2bGaaiyk aiaaysW7caaIYaWaaSaaaeaacaaIXaaabaGaaG4maaaacqGH3daUda WcaaqaaiaaiodaaeaacaaI1aaaaiabg2da9maalaaabaGaaG4naaqa aiaaiodaaaGaey41aq7aaSaaaeaacaaI1aaabaGaaG4maaaacqGH9a qpdaWcaaqaaiaaiodacaaI1aaabaGaaGyoaaaacqGH9aqpdaqjEaqa aiaaiodadaWcaaqaaiaaiIdaaeaacaaI5aaaaaaaaeaacaGGOaGaam ODaiaacMcacaaMe8UaaG4mamaalaaabaGaaGymaaqaaiaaikdaaaGa ey49aG7aaSaaaeaacaaI4aaabaGaaG4maaaacqGH9aqpdaWcaaqaai aaiEdaaeaacaaIYaaaaiabgEna0oaalaaabaGaaG4maaqaaiaaiIda aaGaeyypa0ZaaSaaaeaacaaIYaGaaGymaaqaaiaaigdacaaI2aaaai abg2da9maaL4babaGaaGymamaalaaabaGaaGynaaqaaiaaigdacaaI 2aaaaaaaaeaacaGGOaGaamODaiaadMgacaGGPaGaaGjbVpaalaaaba GaaGOmaaqaaiaaiwdaaaGaey49aGRaaGymamaalaaabaGaaGymaaqa aiaaikdaaaGaeyypa0ZaaSaaaeaacaaIYaaabaGaaGynaaaacqGH3d aUdaWcaaqaaiaaiodaaeaacaaIYaaaaiabg2da9maalaaabaGaaGOm aaqaaiaaiwdaaaGaey41aq7aaSaaaeaacaaIYaaabaGaaG4maaaacq GH9aqpdaqjEaqaamaalaaabaGaaGinaaqaaiaaigdacaaI1aaaaaaa aeaacaGGOaGaamODaiaadMgacaWGPbGaaiykaiaaysW7caaIZaWaaS aaaeaacaaIXaaabaGaaGynaaaacqGH3daUcaaIXaWaaSaaaeaacaaI YaaabaGaaG4maaaacqGH9aqpdaWcaaqaaiaaigdacaaI2aaabaGaaG ynaaaacqGH3daUdaWcaaqaaiaaiwdaaeaacaaIZaaaaiabg2da9maa laaabaGaaGymaiaaiAdaaeaacaaI1aaaaiabgEna0oaalaaabaGaaG 4maaqaaiaaiwdaaaGaeyypa0ZaaSaaaeaacaaI0aGaaGioaaqaaiaa ikdacaaI1aaaaiabg2da9maaL4babaGaaGymamaalaaabaGaaGOmai aaiodaaeaacaaIYaGaaGynaaaaaaaabaGaaiikaiaadAhacaWGPbGa amyAaiaadMgacaGGPaGaaGjbVlaaikdadaWcaaqaaiaaigdaaeaaca aI1aaaaiabgEpa4kaaigdadaWcaaqaaiaaigdaaeaacaaI1aaaaiab g2da9maalaaabaGaaGymaiaaigdaaeaacaaI1aaaaiabgEpa4oaala aabaGaaGOnaaqaaiaaiwdaaaGaeyypa0ZaaSaaaeaacaaIXaGaaGym aaqaaiqaiwdagaGfaaaacqGHxdaTdaWcaaqaaiqaiwdagaGfaaqaai aaiAdaaaGaeyypa0ZaaSaaaeaacaaIXaGaaGymaaqaaiaaiAdaaaGa eyypa0ZaauIhaeaacaaIXaWaaSaaaeaacaaI1aaabaGaaGOnaaaaaa aaaaa@180D@

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