NCERT Solutions for Class 7 Maths Chapter 12 Algebraic Expressions (EX 12.4) Exercise 12.4

Mathematics has constantly been taken into consideration as one of the hardest topics to examine and understand. It is, likewise, one of the most critical topics for students in all the classes. It performs a completely critical function in enhancing a student’s common score. The curriculum is so significant that many find it hard to comply with ideas of Mathematics. It causes confusion among many students. The goal for high school and college students is to understand the proper method and technique for each question asked.Self-reading this subject matter may be very time-consuming and frustrating. Students want a deeper understanding of ideas and formulas. To ease this burden, Extramarks provides accurate and diligently organised solutions. The questions are cautiously divided into unique segments, each with step-by-step solutions. Each question permits school students to take a holistic approach and helps them obtain the best marks. Each step takes one closer to the answer and is actually explained easily to give school students the correct information about the problems they are facing. Through extensive examination of the answers written in the material, school students get the advantage of the study materials and get an idea of every technique, allowing them to clear up any query posed on any subject matter.

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This chapter deals with Algebra and Algebraic formulas. Algebraic formulas began in the 9th century. The first was more in statement form, less mathematical. For example, the Algebraic equation was written as “5 times that plus 3 is 18”, which is basically 5x + 3 = 18. One such non-mathematical equation was Babylonian Algebra. Algebra evolved over time and now comes in a variety of forms.It started with Egyptian Algebra, followed by Babylonian Algebra, Greek geometric Algebra, Diophantine Algebra, Hindu Algebra, Arabic Algebra, and abstract Algebra. Today, the simplest and most convenient forms of Algebra are taught in classes for better understanding.

  • Algebraic Expression

An Algebraic expression is an expression resulting from a combination of variables, constants, and Mathematical operations such as addition, subtraction, multiplication, and division. Algebraic expressions are made up of terms, and equations may have one or more terms. Students will learn about basic concepts used in Algebraic expressions.

  • Constants, Variables, Coefficients, Terms

In Algebraic expressions, fixed numbers are called constants, and constants do not have variables attached to them. For example, 3x – 1 has the constant -1. A variable is an unknown value that exists in an Algebraic expression. For example, 4y + 5z has y and z as variables. A coefficient is a fixed value (real number) assigned to a variable and multiplied by the variable. Example: 5×2 + 3 has 5 as the coefficient of x2. Terms can be constants, variables, or a combination of both. Each term is basically separated by addition or subtraction. For example, 3x + 5, 3x and 5 are the terms.

There are some basic Algebraic formulas used in Mathematics. For instance, an identity is a fixed equation that is true under all conditions. Solutions are available on the NCERT Solutions Class 7 Maths Chapter 12 Exercise 12.4.

NCERT Solutions for Class 7 Maths Chapter 12 Algebraic Expressions (EX 12.4) Exercise 12.4

Understanding concepts is critical for Class 7 students to learn.It helps them think strategically and improves their studies and exam performance. Class 7 is a stage for achieving high grades and excellent marks, but every student needs to work very hard for their exams because it boosts their confidence and helps them achieve higher grades. Therefore, it is very important that students fully understand the concept rather than memorise it in Class 7. The NCERT Solutions Class 7 Maths Chapter 12 Exercise 12.4 helps students by explaining important concepts in a fun and exciting way. Furthermore, by allowing students to quickly review the entire syllabus, the NCERT Solutions for Class 7 Maths, Chapter 12, Exercise 12.4 helps students gain confidence before exams.Class 7 revision notes help students clarify core concepts. Extramarks is one of the best platforms to provide students with practical and convenient CBSE Class 7 revisionnotes, created by experts and updated according to the latest NCERT syllabus. Moreover, it is a platform that offers well-explained NCERT Solutions to all classes. NCERT Solutions Class 7 Maths Chapter 12 Exercise 12.4 and NCERT Solutions Class 7 Mathematics can be downloaded by students to help them revise their entire syllabus and earn more points in their exams.Extramarks has solved the issues and questions from the workout with maximum care and with maximum care and by following all of the recommendations with the help of CBSE.With the help of NCERT Solutions Class 7 Maths Chapter 12 Exercise 12.4, school students can easily solve the questions and recognise the types of questions that may be asked in the exams, as well as study the mark distribution of the subject, so that they can be put together and read at the last minute, just before the examination.

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Access NCERT Solutions for Class 7 Chapter 12 – Algebraic Expressions

The NCERT Solutions Class 7 Maths Chapter 12 Exercise 12.4 are prepared for students who need guidance and are searching for solutions for the preparation of their exams. These NCERT Solutions Class 7 Maths Chapter 12 Exercise 12.4 are in PDF format and are available for download or reading online without spending extra time searching for the right stuff to read. NCERT Solutions Class 7 Maths Chapter 12 Exercise 12.4 offers school students enough guidance and hints associated with the syllabus. The NCERT Solutions Class 7 Maths Chapter 12 Exercise 12.4 helps school students recognise the topics and ideas without putting extra pressure on them. These NCERT Solutions Class 7 Maths Chapter 12 Exercise 12.4 are written in an easy and simple language so that every student can take advantage of the NCERT Solutions Class 7 Maths Chapter 12 Exercise 12.4.

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The NCERT Solutions Class 7 Maths Chapter 12 Exercise 12.4 has its personal significance in growing Mathematics competencies in school students, and for this reason, important terms, formulas, and equations from each have to  be thoroughly revised by school students.The NCERT Solutions Class 7 Maths Chapter 12 Exercise 12.4 solves all of the problems and gives an explanation for them in detail with diagrams, solved problems, and examples so school students can recognise them for a long time.

Exercise 12.4

The NCERT Solutions Class 7 Maths Chapter 12 Exercise 12.4 Algebraic Expressions are available on the Extramarks website.While solving the questions from the NCERT book, school students regularly face trouble and, in the end, pile up their doubts. Extramarks’ professional tutors formulate the NCERT Solutions Class 7 Maths Chapter 12 Exercise 12.4 to help students prepare for their examinations by training them to obtain accurate answers and, hence, get good marks in Mathematics. Students who desire to attain the best marks in their exams are advised to solve the NCERT Solutions Class 7 Maths Chapter 12 Exercise 12.4

The NCERT Solutions Class 7 Maths Chapter 12 Exercise 12.4 Algebraic Expressions contain a lot of mathematical expressions that include variables, numbers, and operations. The chapter includes a lot of topics. Topics included in this chapter are indexed below:

  • In terms of a phrase,
  • Terms that are similar and dissimilar
  • Monomials, Binomials, Trinomials, and Polynomials
  • Addition and Subtraction of Algebraic Expressions
  • Finding The Value of An Expression

NCERT Solutions for Class 7 Maths Chapter 12 Algebraic Expressions Exercise 12.4

Algebraic expressions are not only useful in arithmetic but are also very important in everyday life. People do not always recognise when and where they are using Algebraic expressions, but they are, in one way or another, a part of this introduction to arithmetic. One does not need to be a mathematician to understand, know, and apply Algebra in everyday life. For instance, Once, a shopkeeper stated to the purchaser that he could be presenting the purchaser with five fewer bananas than he had in his possession.The keeper has 12 bananas. Now, the purchaser will use simple Mathematics and pick out that the variety of bananas received is 12 – 5 = 7. However, it’s far more exciting to see that Algebra is used here. The number of bananas obtained with the aid of the purchaser changed into the unknown, so we called it “x” The number of bananas the shopkeeper had changed into 12 and five less than what they had been to deliver to the purchaser.Therefore, an easy Algebraic equation with variable and steady is formed: x + 5 = 12, x = 7.

The significance of Algebraic expressions and their usefulness:

  • Algebraic expressions are used in solvingone-of-a-kind and complicated equations in arithmetic.
  • Algebraic expressions can be seen in computer programming; for example, they are used for inference responsibilities.
  • Algebraic expressions are used in economics to discover  revenue, cost, etc.
  • In one-of-a-kind fields of arithmetic, for instance, trigonometry, geometry, etc., Algebraic expressions are required to remedy unknown angles and values.
  • Algebra is beneficial for boosting one’s logical reasoning potential and aptitude.
  • Making important and large decisions in mathematics and in real life becomes a piece of cake if one has a solid understanding of algebra.

Class 7 Maths Chapter 12 Exercise 12.4 is needed for constructing students’ Mathematics basis and making their conceptual understanding of the subject stronger.There are 14 chapters in the Class 7 Mathematics syllabus, and students need to be thorough with them all. Students should solve the exercise questions from the NCERT Solutions For Class 7 Maths Chapter 12 Exercise 12.4 and go through the examples for a clear understanding of the concepts. Students should practise  Maths Class 7 Chapter 12 Exercise 12.4 and solve questions to enhance their ability and knowledge. They should keep separate notes for revision and formulation. They must learn how to apply the formulation and practise questions associated with it. They must also learn to ask unique sorts of questions and comply with their patterns. They should learn short-reduced strategies for calculations as they will need them to increase their control skills for a while.

Q.1

Observe the patterns of digits made from line segments of equal length. You will find such segmented digits on the display of electronic watches or calculators.

If the number of digits of formed is taken to be n, the number of segments required to form n digits is given by the algebraic expression appearing on the right of each pattern. Hoe many segments are required to form 5, 10, 100 digits of the kind 6, 4, 8.

Ans

a. It is given that the number of segments required to form n digits of the kind 6 is (5n + 1)

Number of segments required to form 5 digits =( 5×5+1 )=26 Number of segments required to form 5 digits =( 5×10+1 )=51 Number of segments required to form 5 digits =( 5×100+1 )=501 MathType@MTEF@5@5@+=feaaguart1ev2aaatCvAUfKttLearuGu1bxzLbIrVjxyKLwyUbqeduuDJXwAKbYu51MyVXgatCvAUfeBSjuyZL2yd9gzLbvyNv2CaeHbd9wDYLwzYbItLDharyavP1wzZbItLDhis9wBH5garqqr1ngBPrgifHhDYfgasaacH8MrFz0xbbf9q8WrFfeuY=Hhbbf9v8qqaqFr0xc9pk0xbba9q8WqFfea0=yr0RYxir=Jbba9q8aq0=yq=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@0EB1@

b. It is given that the number of segments required to form n digits of the kind 4 is (3n + 1)

Number of segments required to form 5 digits =( 3×5+1 )=16 Number of segments required to form 5 digits =( 3×10+1 )=31 Number of segments required to form 5 digits =( 3×100+1 )=301 MathType@MTEF@5@5@+=feaaguart1ev2aaatCvAUfKttLearuGu1bxzLbIrVjxyKLwyUbqeduuDJXwAKbYu51MyVXgatCvAUfeBSjuyZL2yd9gzLbvyNv2CaeHbd9wDYLwzYbItLDharyavP1wzZbItLDhis9wBH5garqqr1ngBPrgifHhDYfgasaacH8MrFz0xbbf9q8WrFfeuY=Hhbbf9v8qqaqFr0xc9pk0xbba9q8WqFfea0=yr0RYxir=Jbba9q8aq0=yq=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@0E9B@

c. It is given that the number of segments required to form n digits of the kind 8 is (5n + 2)

Number of segments required to form 5 digits =( 5×5+2 )=27 Number of segments required to form 5 digits =( 5×10+2 )=52 Number of segments required to form 5 digits =( 5×100+2 )=502 MathType@MTEF@5@5@+=feaaguart1ev2aaatCvAUfKttLearuGu1bxzLbIrVjxyKLwyUbqeduuDJXwAKbYu51MyVXgatCvAUfeBSjuyZL2yd9gzLbvyNv2CaeHbd9wDYLwzYbItLDharyavP1wzZbItLDhis9wBH5garqqr1ngBPrgifHhDYfgasaacH8MrFz0xbbf9q8WrFfeuY=Hhbbf9v8qqaqFr0xc9pk0xbba9q8WqFfea0=yr0RYxir=Jbba9q8aq0=yq=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@0EBD@

Q.2 Use the given algebraic expression to complete the table of number patterns.

S.No. Expression Terms
1st 2nd 3th 4th 5th 10th 100th
(i) 1 3 5 7 9 – 19 – – –
(ii) 2 5 8 11 – – – – – –
(iii) 5 9 13 17 – – – – – –
(iv) 27 34 41 48 – – – – – –
(v) 2 5 10 17 – – – – – –

 

 

 

 

 

 

Ans

The given table can be completed as: MathType@MTEF@5@5@+=feaaguart1ev2aaatCvAUfKttLearuGu1bxzLbIrVjxyKLwyUbqeduuDJXwAKbYu51MyVXgatCvAUfeBSjuyZL2yd9gzLbvyNv2CaeHbd9wDYLwzYbItLDharyavP1wzZbItLDhis9wBH5garqqr1ngBPrgifHhDYfgasaacH8MrFz0xbbf9q8WrFfeuY=Hhbbf9v8qqaqFr0xc9pk0xbba9q8WqFfea0=yr0RYxir=Jbba9q8aq0=yq=He9q8qqQ8frFve9Fve9Ff0dmeaabaqaciGacaGaaeqabaWaaqaafaaakeaacqqGubavcqqGObaAcqqGLbqzcqqGGaaicqqGNbWzcqqGPbqAcqqG2bGDcqqGLbqzcqqGUbGBcqqGGaaicqqG0baDcqqGHbqycqqGIbGycqqGSbaBcqqGLbqzcqqGGaaicqqGJbWycqqGHbqycqqGUbGBcqqGGaaicqqGIbGycqqGLbqzcqqGGaaicqqGJbWycqqGVbWBcqqGTbqBcqqGWbaCcqqGSbaBcqqGLbqzcqqG0baDcqqGLbqzcqqGKbazcqqGGaaicqqGHbqycqqGZbWCcqqG6aGoaaa@6EB5@

S.No. Expression Terms
1st 2nd 3th 4th 5th … 10th 100th …
(i) 1 3 5 7 9 – 19 – 199 –
(ii) 2 5 8 11 – – – 32 302 –
(iii) 5 9 13 17 – – – 41 401 –
(iv) 27 34 41 48 – – – 90 720 –
(v) 2 5 10 17 – – – 101 10,001 –

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