Specific Heat Formula

Specific Heat Formula

We are all very familiar with what heat is and what it can do. But a concept called specific heat is one that hardly anyone is familiar with. Additionally, we can raise an object’s temperature by one degree using specific heat. Additionally, the topic of specific heat, the Specific Heat Formula, its derivation, and solved examples are covered. Furthermore, the specific heat of various elements varies from one another.

Visit the Extramarks website to learn everything students need to know about the Specific Heat Formula. Highly qualified educators with extensive relevant teaching experience have provided all of the content on the platforms. They are well aware of all the difficulties that students face when it comes to the learning process because they have taught students about the Specific Heat Formula.

For students of various other boards, the notes and solutions for the Specific Heat Formula are also made available in Hindi. These notes, thanks to the subject experts at Extramarks, make understanding the Specific Heat Formula simpler. The notes and solutions for the Specific Heat Formula have been created in accordance with the CBSE syllabus and with consideration for the NCERT books’ organisational scheme.

Specific Heat

The amount of heat needed to raise the temperature of a body by one degree in comparison to the amount of heat required to raise the temperature of an equivalent mass of liquid (water) by one degree is known as specific heat. Additionally, we use the term in a more specific sense to refer to the number of calories of heat needed to raise a substance’s temperature by one degree Celsius per gram.

Simply put, it is the ratio of the amount of heat needed to raise an object’s temperature by one degree in comparison to the same amount of heat needed to raise the temperature of water by one degree. On the Extramarks website and mobile application, under the Specific Heat Formula notes and solutions, are the solved examples that can be referred to. The Specific Heat Formula notes and solutions have been put together by some of the top subject-matter experts working with Extramarks to make learning simpler and more interesting for students.

The notes and solutions for the Specific Heat Formula are extremely user-friendly for students and dynamic in style. The Specific Heat Formula notes are updated in accordance with the CBSE curriculum and relate to the structure of the NCERT books, according to experts. Some of Extramarks’ top translators put together the Hindi translation of the Specific Heat Formula notes and solutions. Students can use the solutions to the Specific Heat Formula.

Specific Heat Formula

As was previously mentioned, the relationship between an object’s temperature change and water is known as the specific heat.

The formula also looks like this:

Energy in heat = (mass of the object or substance) Heat specifically (Change in temperature)

Q = m × c × ΔT

Or

Q = mcΔT

Derivation of Specific Heat Formula

The heat energy is expressed as Q = in Joules (J)

m = denotes the substance’s mass in kilogrammes (kg)

The specific heat is expressed in joules per kilogramme (J/kgk) by the symbol c.

The symbol”Δ” refers to the change symbol.

The temperature change in kelvins is indicated by the symbol Δt.

Solved Examples on Specific Heat Formula

Example 1

If the specific heat of gold is 129 J/kg⋅k. Then what quantity of heat energy is required to raise the temperature of 100 g of gold by 50.0 K?

Solution:

First of all, write down the things given in the question

Mass of the gold = 100 g converting it into kg, we get 0.100 kg.

Specific heat = 129 J/kg⋅k.

Temperature = 50.0 K

Calculation:

Q = mcΔT

Q = (0.100 kg) (129 J/kg⋅k) (50.0 K)

So, the energy required to raise the temperature of 100 g gold is 645 J.

Example 2

Suppose a pot is heated by transferring 1676 KJ of heat energy to the water. Moreover, if there is 5.000 kg of water in the pot and the temperature is raised by 80.0 K then find the specific heat of water?

Solution:

Let’s write down the things given in the question

Mass (m) = 5.00 kg

Temperature (T) = 80.0 K

Specific heat (c) = 1676 KJ

Now we have to convert the specific heat into Joules because it is in Kilojoules.

So, the conversion is like this

1 KJ = 1,000 J

So, 1676 KJ = 1,000 × 1676 = 16,76,000 J

Now put all the values in the formula. But, before that, we have to reorganize the formula to find specific heat.

Q = mcΔT → c = Q/mΔT

Now putting values in the rearranged formula

C = 1676000/(5.00kg)(80.0)

C = 4190 J/kg⋅k

Hence, the specific heat of water is 4190 J/kg⋅k.